Answer:
The null hypothesis is ![H_0 : p \le 0.50](https://tex.z-dn.net/?f=H_0%20%3A%20p%20%5Cle%200.50)
The Alternative hypothesis is ![H_a : p > 0.50](https://tex.z-dn.net/?f=H_a%20%3A%20p%20%3E%200.50)
The test statistics is ![Z = 0.985](https://tex.z-dn.net/?f=Z%20%3D%20%200.985)
The conclusion
There is no sufficient evidence to draw the conclusion that more than half of those that are used the drug experienced relief
Step-by-step explanation:
From the question we are told that
The number of subjects reported experiencing significant relief from their symptoms is ![x = 108](https://tex.z-dn.net/?f=x%20%3D%20%20108)
The sample size is ![n = 202](https://tex.z-dn.net/?f=n%20%3D%20202)
The level of significance is ![\alpha = 0.01](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%200.01)
The objective of this experiment is to know whether more than half of those who took the drug where relieved
The null hypothesis is ![H_0 : p \le 0.50](https://tex.z-dn.net/?f=H_0%20%3A%20p%20%5Cle%200.50)
The Alternative hypothesis is ![H_a : p > 0.50](https://tex.z-dn.net/?f=H_a%20%3A%20p%20%3E%200.50)
Where p is the population proportion.
Generally the sample proportion. is mathematically represented as
![\r p = \frac{x}{n}](https://tex.z-dn.net/?f=%5Cr%20p%20%3D%20%20%5Cfrac%7Bx%7D%7Bn%7D)
![\r p = \frac{108}{202}](https://tex.z-dn.net/?f=%5Cr%20p%20%3D%20%20%5Cfrac%7B108%7D%7B202%7D)
![\r p = 0.5347](https://tex.z-dn.net/?f=%5Cr%20p%20%3D%200.5347)
Now the test statistics is mathematically represented as
![Z = \frac{\r p - p}{\sqrt{\frac{p(1-p)}{n} }}](https://tex.z-dn.net/?f=Z%20%3D%20%20%5Cfrac%7B%5Cr%20p%20-%20p%7D%7B%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%20%7D%7D)
substituting values
![Z = \frac{0.5347 - 0.50}{\sqrt{\frac{0.50(1-0.50)}{202} }}](https://tex.z-dn.net/?f=Z%20%3D%20%20%5Cfrac%7B0.5347%20-%200.50%7D%7B%5Csqrt%7B%5Cfrac%7B0.50%281-0.50%29%7D%7B202%7D%20%7D%7D)
![Z = 0.985](https://tex.z-dn.net/?f=Z%20%3D%20%200.985)
Generally the p-value is mathematically evaluated using Excel formula as
![p-value =1 - 0.8377](https://tex.z-dn.net/?f=p-value%20%3D1%20-%200.8377)
![p-value =0.162](https://tex.z-dn.net/?f=p-value%20%3D0.162)
Comparing the p-value to the level of significance we see that the p-value is greater than the level of significance
This means the the null hypothesis would not be rejected
Hence there is no sufficient evidence to draw the conclusion that there are more than half of those that are using the drug experience relief