1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andreev551 [17]
3 years ago
15

A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for random sampleof 1044 pe

ople age 15 or older, the mean amount of time spent eating or drinking per day is 1.44 hours with a standarddeviation of 0.57 hour. (A.) A histogram of time spent eating and drinking each day is skewed right. Use the result to explain why a large samplesize is needed to construct a confidence interval for the mean time spent eating and drinking each day.A. The distribution of the sample mean will never be approx. normalB. The distribution of the sample mean will always be approx. normalC. Since the distribution of time eating and drinking each is normally distributedthe sample must be large so that the distribution of the sample mean will be apprx. NormalD. Since the distribution of time spent eating and drinking each day is not normally distributed (skewed right), the sample must be large so that the distribution of the sample mean will be approx. normal.
(B) In 2010, there were over 200 million people nationally age 15 or older. Explain why this, along with the fact that that the data were obtained using a random sample, satisifies the requirements for constructing a confidence interval.A. The sampe size is greater than 5% of the population.B. The sample size is less than 10% of the populationC. The sample size is greater than 10% of the populationD. The sample size is less than 5% of the population.
(C.) Determine and interpret a 95% confidence interval for themean amount of time Americans age 15 older spend eating and drink each day.A. the nutritionist is 95% confident that the mean amount of time spent eatingand drinking per day is between blank and blank hours.B. the nutritionist is 95% confident that the amount of time spent eating or drinking per day forany individuals is between blank and blank hours.C. There is a 95% probability that the meant amount of time spent eating or drinking per day is between blank and blank hours.D. The requirements for constructing a confidence interval are not satisfied.(d) Could the interval be used to estimate the mean amount of time a 9 year old spends eating and drinking each day?A. No, the interval is about individual time spent eating or drinking per day and cannot be used to find the mean time spent eating or drinking per day.B. No the intreval is about people age 15 or older. The mean amount of time spent eatinf or drinking per day for 9 year olds may differ.C. Yes, the interval is about individual time spent eating or drinking per dat and can be used to find the mean amount of time a 9 year old spends eating and drinking each day.D. Yes, the interval is about the mean amount of time spent eating or drinking per day for the 9 year olds.E. A confidence interval could not be constructed in part (C)D. could the interval be uses to est
Mathematics
1 answer:
Evgesh-ka [11]3 years ago
3 0

Answer:

A) D

B) B

C) C

D) B

Step-by-step explanation:

The complete question is:

A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for random sampleof 1044 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.44 hours with a standarddeviation of 0.57 hour. (A.) A histogram of time spent eating and drinking each day is skewed right. Use the result to explain why a large samplesize is needed to construct a confidence interval for the mean time spent eating and drinking each day.A. The distribution of the sample mean will never be approx. normalB. The distribution of the sample mean will always be approx. normalC. Since the distribution of time eating and drinking each is normally distributedthe sample must be large so that the distribution of the sample mean will be apprx. NormalD. Since the distribution of time spent eating and drinking each day is not normally distributed (skewed right), the sample must be large so that the distribution of the sample mean will be approx. normal.

(B) In 2010, there were over 200 million people nationally age 15 or older. Explain why this, along with the fact that that the data were obtained using a random sample, satisifies the requirements for constructing a confidence interval.A. The sampe size is greater than 5% of the population.B. The sample size is less than 10% of the populationC. The sample size is greater than 10% of the populationD. The sample size is less than 5% of the population.

(C.) Determine and interpret a 95% confidence interval for themean amount of time Americans age 15 older spend eating and drink each day.A. the nutritionist is 95% confident that the mean amount of time spent eatingand drinking per day is between blank and blank hours.B. the nutritionist is 95% confident that the amount of time spent eating or drinking per day forany individuals is between blank and blank hours.C. There is a 95% probability that the meant amount of time spent eating or drinking per day is between blank and blank hours.D. The requirements for constructing a confidence interval are not satisfied.

(D) Could the interval be used to estimate the mean amount of time a 9 year old spends eating and drinking each day?A. No, the interval is about individual time spent eating or drinking per day and cannot be used to find the mean time spent eating or drinking per day.B. No the intreval is about people age 15 or older. The mean amount of time spent eatinf or drinking per day for 9 year olds may differ.C. Yes, the interval is about individual time spent eating or drinking per dat and can be used to find the mean amount of time a 9 year old spends eating and drinking each day.D. Yes, the interval is about the mean amount of time spent eating or drinking per day for the 9 year olds.E. A confidence interval could not be constructed in part (C)D

A) a large sample size ensures normal distribution

B) a good sample size is around 10% of the population

C) confidence interval is a range of value and defines probability that mean of the population will lie with in the range

D) The data given is for 15 years and older so it can't be used for 9 years and younger

You might be interested in
7 × (–3) × (–2)2 = ? <br><br> A. 84<br> B. 48<br> C. –84<br> D. –48
Dahasolnce [82]


7 × (-3) ×(-2)2 =

7 × -3 × -4 = (you have to eliminate all parenthesis in the equation.)

7 × -12 = -84

so your answer would be: C

3 0
3 years ago
Read 2 more answers
FREE BRAINLIEST!! ill also answer questions that you have posted if you answer correctly!!!! (22pts)
GenaCL600 [577]

Answeri think its b lmk if im right or wrong :)

Step-by-step explanation:

8 0
3 years ago
Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. Tha
Brums [2.3K]

Answer:

The length of each side of the city is 250b

Step-by-step explanation:

Given

a = 20 --- tree distance from north gate

b =14 --- movement from south gate

c = 1775 --- movement in west direction from (b)

See attachment for illustration

Required

Find x

To do this, we have:

\triangle ADE \sim \triangle ACB --- similar triangles

So, we have the following equivalent ratios

AE:DE = AB:CB

Where:

AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775

Substitute these in the above equation

20:x/2 = 20 + x + 14: 1775

20:x/2 = x + 34: 1775

Express as fraction

\frac{20}{x/2} = \frac{x + 34}{1775}

\frac{40}{x} = \frac{x + 34}{1775}

Cross multiply

x *(x + 34) = 1775 * 40

Open bracket

x^2 + 34x = 71000

Rewrite as:

x^2 + 34x - 71000 = 0

Expand

x^2 + 284x -250x - 71000 = 0

Factorize

x(x + 284) -250(x + 284)= 0

Factor out x + 284

(x - 250)(x + 284)= 0

Split

x - 250 = 0 \ or\ x + 284= 0

Solve for x

x = 250 \ or\ x =- 284

x can't be negative;

So:

x = 250

6 0
3 years ago
PLEASE HELP FAST! I'LL LIST U BRAINIEST IF U ANSWER RIGHT!
sattari [20]

Answer:

Part A) x = -3

Part B) x = 1, x = -7

Part C) x < -7

Part D) 2

Step-by-step explanation:

<h3>Part A)</h3>

2(x - 3) = 3x - 3

<em>open the parenthesis</em>

2 * x - 2 * 3 = 3x - 3

2x - 6 = 3x - 3

<em>subtract 2x from both sides</em>

2x - 2x - 6 = 3x - 2x - 3

-6 = x - 3

<em>add 3 to both sides</em>

-6 + 3 = x

-3 = x

<h3>Part B)</h3>

|2x + 6| = 8

<em>split this into two equations:</em>

<em>2x + 6 = 8</em>

<em>&</em>

<em>2x + 6 = -8</em>

2x + 6 = 8

2x = 8-6

2x = 2

x = 1

2x + 6 = -8

2x = -8 - 6

2x = -14

x = -7

<h3>Part C)</h3>

-5(x + 1) > 30

<em>open the parenthesis</em>

-5x - 5 > 30

<em>add 5 to both sides</em>

-5x > 35

<em>divide both sides by -5</em>

x > -7

<em>since you divided by a negative, flip the sign.</em>

x < -7

<h3>Part D)</h3>

f(x) = 4x - 3

<em>substitute x for 5</em>

5 = 4x - 3

5 + 3 = 4x

8 = 4x

2 = x

5 0
3 years ago
Help please !! ASAP
Alchen [17]

Answer:

20%

Step-by-step explanation:

6x5=30

20x5=100

7 0
3 years ago
Read 2 more answers
Other questions:
  • HELP I NEED AN ANSWER ASAP!!
    15·2 answers
  • 4(n+11)? please help​
    6·1 answer
  • HELP ME PLEASE. IF YOU HELP ME I'LL LIKE EVERYTHING OF YOURS BUT THE ANSWER HAS TO BE CORRECT IS THIS CORRECT IF IT'S NOT THEN P
    7·1 answer
  • What is the relationship between area in the scale drawing and area on the on the actual tennis court if the scale is 1in.: 5ft.
    6·1 answer
  • 5 points
    15·1 answer
  • Y = 6x<br> 1. Solve:<br> 4x + y = 7
    8·2 answers
  • Name 2 alternate exterior angles do not copy of internet
    10·1 answer
  • A student scored 80 and 93 on her first two quizzes. Write and solve a compound inequality to find the
    15·1 answer
  • Miguel is a baseball pitcher. This season, he struck
    5·1 answer
  • Jenna wants to make a park bench as part of her family's miniature railroad train display. If the display is built to scale wher
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!