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3 years ago

What is the opposite of the opposite of 8 1/4

Mathematics

1 answer:

Alenkasestr [34]3 years ago

8 0

8 1/4
33/4
the opposite is 4/33

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The graph has y-intercept (0, 6) and contains the point (2, 1).

prisoha [69]

Answer:

5x + 2y = 12

Step-by-step explanation:

Direction factor = (2, 1) - (0, 6) = (2, -5)

So, normal factor = (5, 2)

Line: 5x + 2y = k

(0, 6) -> L: 0 + 12 = 12 = k

L: 5x + 2y = 12

5 0

2 years ago

Elizabeth lives in San Francisco and works in Mountain View. In the morning, she has 3 transportation options (take a bus, a cab

mina [271]

Answer:

If Elizabeth randomly chooses her ride in the morning and in the evening, 2/3 is the probability that she'll use a cab exactly one time

3 0

1 year ago

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2854 / 32 A. 89 B. 89 3/16 C. 89 5/16 D. 89 3/8

Marrrta [24]

Its b
2854/32 = 1427/16 = 89 3/16

7 0

3 years ago

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PLEASE CAN SOMEONE HELP????

schepotkina [342]

Answer:

figure it out dummy

Step-by-step explanation:

6 0

2 years ago

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In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

2 years ago