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Artemon [7]
3 years ago
8

How would i solve this? Thank you

Mathematics
1 answer:
dusya [7]3 years ago
4 0
The answer to this problem is A
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Help me with these will mark!
Ksju [112]
Answer: 125/168

Explanation
8 0
2 years ago
What is the answer to this question ? -7+17=
IRISSAK [1]
Well -7+17 would equal 10. Hope this helps!
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3 years ago
Read 2 more answers
The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20. Each d
liberstina [14]

Answer: 0.0516

Step-by-step explanation:

Given : The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of \lambda=20.

The probability mass function for Poisson distribution:-P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

For x= 15 and  \lambda=20 , we have

P(X=x)=\dfrac{e^{-20}(20)^{15}}{15!}=0.0516488535318\approx0.0516

Hence, the probability that exactly 15 defective components are produced in a particular day = 0.0516

7 0
3 years ago
An artist cuts 4 squares with side length x ft from the corners of a 12 ft-by-18 ft rectangular piece of sheet metal. She bends
Kruka [31]

Answer:

V=4x^3-60x^2+216x

Step-by-step explanation:

<u>Volume And Function s</u>

Geometry can usually be joined with algebra to express volumes as a function of some variable. The volume of a parallelepiped of dimensions a,b,c is

V=abc

Our problem consists in computing the volume of a box made with some sheet of metal 12 ft by 18 ft. The four corners are cut by a square distance x as shown in the image below .

If the four corners are to be lifted and a box formed, the base of the box will have dimensions (12-2x)(18-2x) and the height will be x. The volume of the box is

V=x(12-2x)(18-2x)

Operating and simplifying

V=4x^3-60x^2+216x

8 0
3 years ago
Can someone help me with credit recovery
Sindrei [870]

Answer:

Credit recovery is a term used to describe a wide variety of educational strategies and programs that give high school students who have failed a class the opportunity to redo coursework or retake a course through alternate means—and thereby avoid failure and earn academic credit.

Step-by-step explanation:

I'm not sure if this help but if it does good luck with it.

7 0
3 years ago
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