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disa [49]
3 years ago
15

Can u help me awser this

Mathematics
2 answers:
lions [1.4K]3 years ago
6 0
X/5 = -7-3y

x= -35 - 15y
Olin [163]3 years ago
5 0
Y= (x/5 + 7)/3
x/5 + x/5 + 7 + 7 = 0
2x/10 = -14
2x = -140
x = -70

I think... hope it helps
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Write an equation of the line parallel to y=3x−7 that passes through point (2, 4).
MrRissso [65]
Parallel lines share the same slope. y=3x+7 has a slope of 3, so that is the slope of the parallel line. Then use y=mx+b an plug in (2,4).
y=3x+b
4=3(2)+b
4=6+b
b=-2

So the equation is y=3x-2
6 0
3 years ago
How to graph y=7x-1 using the y
kirill [66]
Plot the y-intercept (0,-1) and then from that point go up seven and to the right one. Plot that point, then draw the line between the two points.

Hope this helped! Good luck! :)
8 0
3 years ago
Question 1
storchak [24]

Answer:

(0,-3)

Step-by-step explanation:

To find the point of intersection for the two lines, we solve the two equations simultaneously

x=0, y=-3x=0  y=-3

4 0
3 years ago
Read 2 more answers
Make b the subject a= 1/4 b
dalvyx [7]

<u>Answer</u>:

b =  4a

<u>Step-by-step explanation</u>:

a = \frac{b}{4}

b =  4a

<em>changing sides changes sign division to multiplication.</em>

3 0
2 years ago
Read 2 more answers
A kilogram of seawater contains 1/40 kg of salt. How much salt is there in two buckets of seawater, which contain 500 liters of
never [62]

Two buckets of seawater contain 13\frac{28}{40} kg of salt.

Step-by-step explanation:

Amount of salt in 1 kg water = \frac{1}{40}\ kg

It is given that;

1 liter = 1\frac{12}{125} = \frac{137}{125}\ kg

500 liters = 500*\frac{137}{125} = \frac{68500}{125}

500 liters = 548 kilogram

As,

1 kg of seawater = \frac{1}{40}\ kg of salt

548 kilograms = \frac{1}{40}*548

548 kilograms = 13\frac{28}{40} kilograms of salt

Two buckets of seawater contain 13\frac{28}{40} kg of salt.

Keywords: unit rate, multiplication

Learn more about multiplication at:

  • brainly.com/question/10525991
  • brainly.com/question/10534381

#LearnwithBrainly

5 0
3 years ago
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