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NeTakaya
3 years ago
15

Trains of

Mathematics
1 answer:
AnnyKZ [126]3 years ago
3 0

Answer:

bc they are placed the same if one is multiplied by 10. or you could just multiply the tens place and add that to your 100

140=14×10 and 100 and 4 tens is written 140.

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Find all the points, if any, where the graph of 12x-5y=0 intersects (x+12)^2+(y-5)^2=169.
WITCHER [35]
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169

with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
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insert into I:
12x=0
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-> only intersection is at (0,0) = option B
6 0
3 years ago
Read 2 more answers
Baker, Inc. uses the sum-of-the-years’-digits method to depreciate a $79,600.00 piece of equipment that has an estimated life of
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The book value at the end of year 2 of the equipment depreciated using the sum-of-the-years’-digits method is $65,560.

<h3>What is the book value at the end of  year 2? </h3>

Depreciation is a method used to expense the cost of an asset. Book value is the cost of the asset less the accumulated depreciation.

Sum-of-the-year digits = (remaining useful life / sum of the years ) x  (Cost of asset - Salvage value)

Depreciation expense in year 1:

Sum of the years = 1 +2 +3 +4 + 5 + 6 + 7 + 8 + 9 + 10+ 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210

Undepreciated life of the asset = 20

(20 / 210) x ($79,600 - 4,000) = 7200

Depreciation expense in year 2:

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Book value = 79600 - 7200 - 6840 = $65,560

To learn more about depreciation, please check: brainly.com/question/25552427

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Angelina_Jolie [31]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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