Answer:
The equation of the graphed line is:
Step-by-step explanation:
From the graph, it is clear that the line is a horizontal line at y = 2.
We know that a horizontal line has a slope of 0 because the value of y does not change no matter what the value of x we put in.
In other words, the equation of the horizontal line would always get the form:
y = k
where k is the y-intercept of the line.
Determining the y-intercept of the line:
We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.
From the graph, it is clear
at x = 0, y = 2
Thus, the y-intercept k = 2
Thus, if we substitute the y-intercept k = 2 in the equation y = k, we get the equation
y = 2
Therefore, the equation of the graphed line is:
He makes commission of 15% on everything he sells.....so if he sells 293 worth of stuff, then he would make 15% of 293
15% of 293.....turn ur percent to a decimal..." of " means multiply
0.15 * 293 = 43.95 <==
Multiples of 5 end in 5 or 0 this would mean
5,10,15,20,25,30,35,40 are all multiples of 5
Answer: 30 percent of 20 is 6.
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Step-by-step explanation:
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(n/100) * 20 = 6 ?
Solve for "n" .
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Divide each side of the equation by "20" :
{ (n/100) * 20 } / 20 = 6 / 20 ;
to get:
n/100 = 6/20 ;
↔ 6/20 = n/100 ; solve for "n" ;
Look at the denominators:
20 * ? = 100 ?
100/ 20 = ? ;
100/20 = 5 ;
So, 20 * " 5" = 100 ;
Then 6* 5 = "n" (for the numerator, "n"; in : "n /100" ) ;
→ 6 * 5 = 30 ;
→ n = 30 .
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Answer: 30 percent of 20 is 6.
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Answer:
0.0228 = 2.28% probability that a randomly selected firm will earn more than Arc did last year
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Suppose the mean income of firms in the same industry as Arc for a year is 45 million dollars with a standard deviation of 7 million dollars
This means that 
What is the probability that a randomly selected firm will earn more than Arc did last year?
Arc earned 59 million, so this is 1 subtracted by the pvalue of Z when X = 59.
has a pvalue of 0.9772
1 - 0.9772 = 0.0228
0.0228 = 2.28% probability that a randomly selected firm will earn more than Arc did last year
