There are 8 rows in a theater with 12 seats in each row in the middle of the first three rows 4 seats are broken

melomori [17]

Answer:

108m

Step-by-step explanation:

Hello, to find the height of the bigger triangle, you take the width of the bigger triangle and divide by the width of the smaller triangle like this:

72/0.8=90

Then, you take 90 and you multiply it by the height of the smaller triangle like this:

1.2 x 90= 108

So the height of the bigger triangle is 108m.

6 0

3 years ago

Read 2 more answers

Taxi A charges a fee of $3.50, plus $1.75 per mile. Taxi B charges a few of $1.25, plus $2.00 per mile. At what distance would t

frez [133]

Taxi A
1mile £3.50+£1.75=£5.25
Taxi B
1mile £1.25+£2.00=£3.25

Taxi A
2miles £3.50+£3.50=£7.00
Taxi B
2miles £1.25+£4.00=£5.25

Taxi A
3miles £3.50+£5.25=£8.75
Taxi B
3miles £1.25+£6.00=£7.25

Taxi A
4miles £3.50+£7.00=£10.50
Taxi B
4miles £1.25+£8.00=£9.25

Taxi A
5miles £3.50+£8.75=£12.25
Taxi B
5miles £1.25+£10.00=£11.25

Taxi A
6miles £3.50+£10.50=£14.00
Taxi B
6miles £1.25+£12.00=£13.25

Taxi A
7miles £3.50+£12.25=£15.75
Taxi B
7miles £1.25+£14.00=£15.25

Taxi A
8miles £3.50+£14.00=£17.50
Taxi B
8miles £1.25+£16.00=£17.25

Taxi A
9miles £3.50+£15.75=£19.25 (the same)
Taxi B
9miles £1.25+£18.00=£19.25 (the same)

^^^
They would have to drive 9 miles for the taxi to cost the same.

Hope this helped, this is the longest way to work it out but also the simplest.

6 0

2 years ago

A soccer ball is kicked toward the goal. The height of the ball is modeled by the function h(t) = −16t2 + 48t where t equals the

zlopas [31]

1. The function $h(t)=-16t^{2}+48t$ is a parabola of the form $ax^{2}+bx$ . The the formula for the axis of symmetry of a parabola is $x= \frac{-b}{2a}$ . We can infer from our function that $a=-16$ and $b=48$ , so lets replace those values in our formula:
$x= \frac{-b}{2a}$
$x= \frac{-48}{-2(16)}$
$x= \frac{-48}{-32}$
$x= \frac{3}{2}$
$x=1.5$
We can conclude that to the left of the line of symmetry the ball is reaching its maximum height, and to the right of the line of symmetry the ball is falling.

2. Lets check how much time the ball takes to reach its maximum height and return to the ground. To do that we are going to set the height equal to zero:
$0=-16t^{2}+48t$
$-16t(t-3)=0$
$t=0$ or $t-3=0$
$t=0$ or $t=3$
From our previous point we know that the ball reaches its maximum time at $t=1.5$ , which means that <span>it takes 1.5 seconds to reach the maximum height and 1.5 seconds to fall back to the ground.</span>