All categories

3 years ago

Find the zeros of the function. f(x) = x2 - 6x + 8

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

6 0

The answer is 2.4 hope this helps

Ratling [72]3 years ago

3 0

The zeroes of this function are x = 2, 4.

We can find this by factoring. Factoring x²-6x+8, we get (x-2)(x-4). Now, since we want to find the zeroes, we have to make y equal to zero, or (x-2)(x-4) = 0. Using the zero-product property, we can conclude that if (x-2)(x-4) is 0, x is 2, 4.

You might be interested in

68 more than the quotient of an unknown number and 54 is 72.

Andru [333]

68 + (x / 54) = 72 68 + (x / 54) • 54 = 72 • 54 68 + x = 72 • 54 68 + x = 3,888 68 + x - 68 = 3,888 - 68 x = 3,888 - 68 x = 3,820 I'm pretty sure this is right. Good luck!

4 0

3 years ago

Read 2 more answers

Find the function y1 of t which is the solution of 121y′′+110y′−24y=0 with initial conditions y1(0)=1,y′1(0)=0. y1= Note: y1 is

strojnjashka [21]

Answer:

Step-by-step explanation:

The original equation is $121y''+110y'-24y=0$ . We propose that the solution of this equations is of the form $y = Ae^{rt}$ . Then, by replacing the derivatives we get the following

$121r^2Ae^{rt}+110rAe^{rt}-24Ae^{rt}=0= Ae^{rt}(121r^2+110r-24)$

Since we want a non trival solution, it must happen that A is different from zero. Also, the exponential function is always positive, then it must happen that

$121r^2+110r-24=0$

Recall that the roots of a polynomial of the form $ax^2+bx+c$ are given by the formula

$x = \frac{-b \pm \sqrt[]{b^2-4ac}}{2a}$

In our case a = 121, b = 110 and c = -24. Using the formula we get the solutions

$r_1 = -\frac{12}{11}$

$r_2 = \frac{2}{11}$

So, in this case, the general solution is $y = c_1 e^{\frac{-12t}{11}} + c_2 e^{\frac{2t}{11}}$

a) In the first case, we are given that y(0) = 1 and y'(0) = 0. By differentiating the general solution and replacing t by 0 we get the equations

$c_1 + c_2 = 1$

$c_1\frac{-12}{11} + c_2\frac{2}{11} = 0$ (or equivalently $c_2 = 6c_1$

By replacing the second equation in the first one, we get $7c_1 = 1$ which implies that $c_1 = \frac{1}{7}, c_2 = \frac{6}{7}$ .

So $y_1 = \frac{1}{7}e^{\frac{-12t}{11}} + \frac{6}{7}e^{\frac{2t}{11}}$

b) By using y(0) =0 and y'(0)=1 we get the equations

$c_1+c_2 =0$

$c_1\frac{-12}{11} + c_2\frac{2}{11} = 1$ (or equivalently $-12c_1+2c_2 = 11$

By solving this system, the solution is $c_1 = \frac{-11}{14}, c_2 = \frac{11}{14}$

Then $y_2 = \frac{-11}{14}e^{\frac{-12t}{11}} + \frac{11}{14} e^{\frac{2t}{11}}$

The Wronskian of the solutions is calculated as the determinant of the following matrix

$\left| \begin{matrix}y_1 & y_2 \\ y_1' & y_2'\end{matrix}\right|= W(t) = y_1\cdot y_2'-y_1'y_2$

By plugging the values of $y_1$ and

We can check this by using Abel's theorem. Given a second degree differential equation of the form y''+p(x)y'+q(x)y the wronskian is given by

$e^{\int -p(x) dx}$

In this case, by dividing the equation by 121 we get that p(x) = 10/11. So the wronskian is

$e^{\int -\frac{10}{11} dx} = e^{\frac{-10x}{11}}$

Note that this function is always positive, and thus, never zero. So $y_1, y_2$ is a fundamental set of solutions.

8 0

3 years ago

D=7.9cm. what is the circumference and area of the circle?

In-s [12.5K]

Circumfrence: pi times diameter
7.9* $\pi$
circumfrence is approximatley 24.806

area: $\pi r^2$
a= $\pi$ *(1/2(d))^2
a= 48.99

8 0

3 years ago

Read 2 more answers

What is the answer to <br> -100%+0.58= ?

3241004551 [841]

Answer:

-0.42

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Explain the advantages and disadvantages of a non-linear rate structure.<br>Please, help!

zhannawk [14.2K]

Answer:

advantage: it uses memory very efficiently than linear data structures

disadvantages: Non - linear data structures are quite hard to understand and implement than linear data structures

8 0

2 years ago