Answer:
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Answer:
So the numbers are 12 and -3.
Step-by-step explanation:
In order to solve this problem we will attribute variables to the numbers, the first one will be "x" and the second one will be "y". From the first sentence we know that the subtraction of the two numbers is equal to 15, so we have:
x - y = 15
Then the problem states that one-third of the sum of the number is equal to one quarter of the first number, so we have:
(1/3)*(x+y) = x/4
Since we now have two equations and two variables we can solve for x and y. From the first equation we have:
y = x - 15
Using this expression for the value of y in the second equation:
(1/3)*(x + x - 15) = x/4
(1/3)*(2*x - 15) = x/4
2*x - 15 = 3*x/4
2*x - 3*x/4 = 15
(8*x - 3*x)/4 = 15
5*x/4 = 15
5*x = 60
x = 60/5 = 12
y = x - 15 = 12 - 15 = -3
So the numbers are 12 and -3.
There are a lot of solutions to this problem, so I'm only going to list 10. The only requirement is that the quadrilateral must be a rectangle with a perimeter of 120 meters.
1) 30, 30, 30, 30. I know that this is a square, but it should still be a solution since all squares are rectangles.
2) 50, 50, 10, 10.
3) 55, 55, 5, 5.
4) 45, 45, 15, 15.
5) 40, 40, 20, 20.
6) 35, 35, 25, 25.
7) 36, 36, 24, 24.
8) 18, 18, 52, 52.
9) 14, 14, 48, 48
10) 6, 6, 54, 54.
9 + 5k + 10y + 3y - 8k
9 - 3k +13y
