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2 years ago

Help me out please! Anybody? I’m so confused

Mathematics

2 answers:

AlexFokin [52]2 years ago

8 0

Vas happenin!!!

So you plug in the 3 into the equation 12-3(3)/2 + 3 [2(3)-4/3
You multiply the parentheses first
3 times 3 is 9
2 times 3 is 6
Then you plug it in again 12-9 / 2 plus 6-4/3
12-9 is 2/2 which is 1
1 plus 6-4/3
6-4 is 2
2/3 is you can stay it as a fraction or the decimal form is 1.5

1 plus 1.5 is 2.5
So your answer in decimal form is 2.5
Fraction form is 2 1/2

Hope this helps *smiles*
Sorry if it’s wrong

pogonyaev2 years ago

5 0

Hope it helpssss !!!!!

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Answer:

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

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= $\frac{1}{2}(\text{GE+OF)}\times (\text{OG})$

= $\frac{1}{2}(3+6)\times 4$

= 18 units²

Area of trapezoid GCDE = $\frac{1}{2}(\text{GC+DE)}\times (\text{GE})$

= $\frac{1}{2}(7+2)\times 3$

= 13.5 units²

Area of triangle AFH = $\frac{1}{2}(\text{Base})\times (\text{Height})$

= $\frac{1}{2}(5)(2)$

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Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)

= 88 - (18 + 13.5 + 5)

= 88 - 36.5

= 51.5 units²

Therefore, area of the given polygon is 51.5 units²

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3 years ago

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In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th

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Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

Probability that the students passed the second exam = P(S) = 0.72

Probability that the students passed both exams = $P(F \bigcap S)$ = 0.58