Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Can you take the quantity [ x + y ] and square it ?
Can you take the quantity [ x + 2y ] and square it ?
Then you should have no trouble with the square of (.9x + .8y) .
The square of any binomial (expression with 2 terms) is
(square of the first term)
+ (square of the second term)
+ 2 times (product of the terms) .
Answer:
WOMP WOMP WOMP!!!
Step-by-step explanation:
Answer:
The answer is that c = 6
Step-by-step explanation:
Answer: 62.83
Step-by-step explanation:
