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erik [133]
3 years ago
6

BRAINLIEST !!!!!! NEED HELP ASAP!!!! The variable that the experimenter changes is the: Question 3 options: Dependent variable I

ndependent variable Controlled variable
Chemistry
1 answer:
Julli [10]3 years ago
6 0

Answer: dependent

Explanation:

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Using the periodic table, choose the more reactive nonmetal.<br> Br or As
vladimir2022 [97]
Br
First of all, As is a metalloid, not a nonmetal. Second of all, as the rows get higher on the periodic table, the elements are more reactive. As you move right on the periodic table, the elements become more reactive.
3 0
3 years ago
Diol oxidation without C-C bond breakage ....which products are formed??
babunello [35]
If its oxidised, water and carbon dioxide is formed.
4 0
3 years ago
Two metals (Metal A and Metal B) are both exposed to a laser which emits photons that have a greater energy than the work functi
Tresset [83]

Answer:

shorter than

equal to

Explanation:

Let us go back to the Einstein photoelectric equation;

KE = E - Wo

Where

KE = kinetic energy of the photoelectron

E = energy of the incident photon

Wo = work function of the metal

But KE = 1/2mv^2

Thus the velocity of the emitted photoelectron  is determined by the kinetic energy of the emitted photoelectron.

Since the work function of metal A is smaller than that of metal B, the kinetic energy of photoelectrons emitted from metal A is greater than that of photoelectrons emitted from metal B . Therefore, the velocity of electrons from metal A is greater than those from metal B.

From de Broglie relation;

λ = h/mv

Where;

λ = de Broglie wavelength

h = Plank's constant

m = mass

v = velocity

Metal A producing electrons with greater velocity will lead to a shorter de Broglie wavelength compared to those from metal B.

The number of photoelectrons ejected is determined by the intensity of the photons and not the energy of the incident photons or the work function of the metals. Since the two metals are exposed to the the same laser, equal number of photoelectrons are produced for metals A and B.

8 0
3 years ago
Imagine you are at a local water park on a hot summer day and your feet begin to get hot from the cement. Looking ahead, you not
valkas [14]

Answer:

Sand has less specific heat than water.

Explanation:

Specific Heat is amount of heat needed per unit mass, to raise temperature by 1 degree celsius.

More specific heat means more heat energy needed to increase temperature. It implies - more time needed to absorb heat, increase temperature; and also more time needed to lose its heat.

Less specific heat means less heat energy needed to increase temperature. It implies - less time needed to absorb heat, increase temperature; and also less time needed to lose its heat.

Sand has less specific heat than water. So, it needs less heat absorption to increase temperature by per unit (celsius) ; than water. Hence, same level of heat to both sand & water ; increase temperature of sand more than water, & make it more hot.

8 0
3 years ago
What is the rule of thumb for the activity trends of metals and nonmetals? Explain and give examples.
pentagon [3]

This for metal......the farther to the left the more reactive they are. Group 1 metals, which include sodium and potassium, are so highly reactive that they do not exist in nature by themselves


Thats non metals..........the farther to the right the more reactive they are *with the exception of group 18* which are the noble gases and do not react at all. The most reactive are group 17, which include fluorine and chlorine. These non-metals, like group 1, rarely exist by themselves because of their high reactivity.

5 0
4 years ago
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