3 zots = 7 wots
3 zots × (3 dooms/2 zots) = ⁹/₂ dooms
⁹/₂ dooms × (7 farzes/4 dooms) = ⁶³/₈ farzes
⁶³/₈ farzes × (4 bings/9 farzes) = ⁷/₂ bings
⁷/₂ bings × (2 wots/1 bing) = 7 wots
Explanation:
Let us assume that the given data is as follows.
mass of barium acetate = 2.19 g
volume = 150 ml = 0.150 L (as 1 L = 1000 ml)
concentration of the aqueous solution = 0.10 M
Therefore, the reaction equation will be as follows.

Hence, moles of
=
.......... (1)
As, No. of moles =
Hence, moles of
will be calculated as follows.
No. of moles =
=
(molar mass of
is 255.415 g/mol)
= 
Moles of
= 
= 0.01715 mol
Hence, final molarity will be as follows.
Molarity = 
= 
= 0.114 M
Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.
The answer is [OH⁻] = 1 x 10⁻⁴.
[OH⁻] = H₂O ÷ [H₃O⁺]
[OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻¹⁰
[OH⁻] = 10⁻⁴
Answer:
10. F
11. A
12. B
13. C
14. G
15. A
16. F
17. B
18. D
19. E
20. B
Explanation:
im sorry
ik some are probably incorrect