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seraphim [82]
2 years ago
12

According the course handbook at a large university, the length of classes held on Monday (M), Wednesday (W), and Friday (F) hav

e a mean of 50 minutes and standard deviation of 5 minutes. The length of classes held on Tuesdays (T) and Thursdays (R) have a mean of 75 minutes and standard deviation of 7 minutes. The college provost is concerned that professors that teach classes on Tuesdays and Thursdays are dismissing their students too early. To determine if there is credibility about this concern the provost selects a random sample of 30 TR classes and 30 MWF classes and determines the length of each class. Let

Mathematics
1 answer:
taurus [48]2 years ago
7 0
It is C because it also has to require good grammar and English. Especially commas
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A marketing research company needs to estimate the average total compensation of CEOs in the service industry. Data were randoml
mezya [45]

SOLUTION:

Step 1 :

In this question, we are told that a marketing research company needs to estimate the average total compensation of CEOs in the service industry.

We also have that: Data were randomly collected from 38 CEOs and the 98% confidence interval was calculated to be ($2,181,260, $5,836,180).

Then, we are asked to find the margin error for the confidence interval.

Step 2:

We need to recall that:

\text{Higher Confidence Interval, CI}_{H\text{ = }}X\text{ + }\frac{Z\sigma}{\sqrt[]{n}}\text{Lower Confidence Interval , CI}_{L\text{ }}=\text{ X - }\frac{Z\sigma}{\sqrt[]{n}}

It means that:

\vec{}X\text{ = }\frac{CI_{H\text{ }}+CI_L}{2}\text{Margin of error, }\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{CI_{H\text{ - }}CI_L}{2}

where,

CI_H\text{ = }$$5,836,180$\text{ }$$$CI_{L\text{ }}=\text{ }2,181,260

putting the values into the equation for the margin of error, we have that:

\text{Margin of error,}\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{5,836,180\text{  - }2,181,260\text{ }}{2}\begin{gathered} =\text{ }\frac{3654920}{2} \\ =1,\text{ 827, 460} \end{gathered}

CONCLUSION:

The margin error for the confidence interval is 1, 827, 460

5 0
9 months ago
-3/4 plus -8/9
Vinil7 [7]

Answer:

-3/4 -8/9

take LCM

<u>-3*9-8*4</u>

    36

<u>-27 -32</u>

  36

-59/36

Step-by-step explanation:

3 0
2 years ago
Pleaaase help me, it'll give you 50 points and i'll mark you as brainliest or whatever it's called.
gogolik [260]

Answer:

3/16

Step-by-step explanation:

5 0
3 years ago
Gillian said that if all the students and mr. Romano had each picked just 2 1/2 quarts of raspberries, they would have had enoug
EastWind [94]

Answer:

Step-by-step explanation:

i dont know

8 0
2 years ago
What is the best description of the data in the histogram
Bingel [31]
A-the data set is symmetrical
7 0
2 years ago
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