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coldgirl [10]
3 years ago
12

2y + 3 divided by 21y2 + 6y3 − 22

Mathematics
2 answers:
Brut [27]3 years ago
6 0

Answer:

2/7• [ 71x-77 ]

Step-by-step explanation:

2x+3 divided by 21•x•2+6x•3-22

⬆️Re-Write

2x+3/21x•2+18x-22

⬆️Collect

20x+3/21x•2-22

⬆️Factor Expression

2(10x+3/21x-11)

⬆️Reduce

2(10x+1/7x-11)

⬆️Calculate

2(71/7x-11)

⬆️Factor

2•1/7•(71x-77)

⬆️Calculate

2/7x(71x-77)

⬆️Answer


I hope this helps and the X variable is the Y.

Lapatulllka [165]3 years ago
4 0

Answer:

21y^2+6y^3-11y+3

Step-by-step explanation:

Divide the numbers 22÷2=11

<em>Hope this helps!!</em>

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3 years ago
The masses mi are located at the points Pi. Find the moments Mx and My and the center of mass of the system. m1 = 4, m2 = 3, m3
viva [34]

Answer:

M_x= 8

M_y = 6

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

Step-by-step explanation:

Center of mass: Center of mass of an object is a point on the object. Center of mass is the average position of the system.

Center of mass of a triangle is the centriod of a triangle.

Given that m₁= 4, m₂=3, m₃=3 and the points are P₁(2,-3), P₂(-3,1) and P₃(3,5)

M_x = ∑(mass × x-co-ordinate)

M_y = ∑(mass × y-co-ordinate)

Therefore  

M_x = (4×2)+{3×(-3)}+(3×3)

     =8

M_y = {4×(-3)}+{3×1}+(3×5)

    =6

The x co-ordinate of the center of mass is the ratio of M_x to the total mass.

The y co-ordinate of the center of mass is the ratio of M_y to the total mass.

Total mass (m) = m₁+ m₂+ m₃

                        = 4+3+3

                        =10

The x co-ordinate of the center of mass is \frac {8}{10} = \frac {4}{5}

The y co-ordinate of the center of mass is \frac{6}{10}=\frac{3}{5}

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

4 0
3 years ago
Y-x=4 and x is three times the value of y, what is the value of x+y?
slega [8]

Answer:

x+y=-8

Step-by-step explanation:

y-x=4

x=3y

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y=4/(-2)

x=3y

y=-2

x=3*(-2)

x=-6, y=-2 then

x+y=-6-2=-8

6 0
3 years ago
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