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frozen [14]
3 years ago
13

(6x^1) ^2 Please show all work

Mathematics
1 answer:
katen-ka-za [31]3 years ago
6 0
1. Apply a^1= a , rule.
x^1 = x
=(6x)^2

2. Then apply exponent rule. (a*b)=a^n b^n
=6^2 x^2

3.6^2 = 36 , because 6 x 6 = 36
Now, apply x^2
=36x^2
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Answer:

The value of k that makes the relationship shown in the table below proportional is \mathbf{\frac{1}{2}}

Step-by-step explanation:

The relation is proportional if y=kx \:or\:k=\frac{y}{x}

Putting values of x and y to find k.

For x =2 and y =1 k is: k=\frac{y}{x}=\frac{1}{2}

For x =4 and y =2 k is: k=\frac{y}{x}=\frac{2}{4} =\frac{1}{2}

For x =6 and y = 3 k is: k=\frac{y}{x}=\frac{3}{6} =\frac{1}{2}

For x = 8 and y = 4 k is: k=\frac{y}{x}=\frac{4}{8} =\frac{1}{2}

For x =10 and y = 5 k is: k=\frac{y}{x}=\frac{5}{10} =\frac{1}{2}

So, The value of k that makes the relationship shown in the table below proportional is \mathbf{\frac{1}{2}}

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Alekssandra [29.7K]

Answer:

See Explanation

Step-by-step explanation:

Given

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We can assume the parent function to be:

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B = \frac{\pi}{5}

Using the calculated values of A,\ B\ and\ c. This implies that, the following transformations occur on the parent function:

  • <em>Vertically stretched by </em>3<em />
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