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disa [49]
3 years ago
8

WHAT'S THE ANSWER???????????????

Mathematics
2 answers:
Sidana [21]3 years ago
8 0
It’s probably 4.5........maybe I’m really not that sure but u can try
Sever21 [200]3 years ago
4 0

Answer:

In between 4 and 5 is where it would go (Also the person removed my answer now i have lost a brainiest)

Step-by-step explanation:

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xenn [34]

Answer:

use rise over run! this means  "rise" (being the change in y, going up or down) divided by the "run" (being the change in x, going from left to the right).

Step-by-step explanation:

3 0
3 years ago
According to Scarborough Research, more than 85% of working adults commute by car. Of all U.S. cities, Washington, D.C., and New
tamaranim1 [39]

Answer:

The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

Here the population standard deviation (σ) is not provided. So the confidence interval would be computed using the <em>t</em>-distribution.

The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) using the <em>t</em>-distribution is:

CI=\bar x\pm t_{\alpha /2,(n-1)}\frac{s}{\sqrt{n}}

Given:

\bar x=27.97\\s=10.04\\n=25\\t_{\alpha /2, (n-1)}=t_{0.01/2, (25-1)}=t_{0.005, 24}=2.797

*Use the <em>t</em>-table for the critical value.

Compute the 99% confidence interval as follows:

CI=27.97\pm 2.797\times\frac{10.04}{\sqrt{25}}\\=27.97\pm5.616\\=(22.354, 33.586)\\\approx(22.35, 33.59)

Thus, the 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).

8 0
3 years ago
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