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Mandarinka [93]
3 years ago
11

Which of the following expressions are polynomials and which are not (why?) 1/x^3 +x^2

Mathematics
1 answer:
goldenfox [79]3 years ago
5 0

Answer:

none shown

Step-by-step explanation:

1/x^3 = x^(-3) has a negative exponent. It does not match the requirement that exponents be a non-negative integer. Therefore, any expression containing 1/x^3 will not be a polynomial.

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Unit 3 Exam
lbvjy [14]

Answer:

Scalene is the right option.

Step-by-step explanation:

A scalene triangle has all its sides of different lengths.

6 0
3 years ago
mai and priya were on scooters. mai traveled 15 meters in 6 seconds priya traveled 22 meters in 10 seconds. who was moving faste
Eduardwww [97]

Answer:

Its Mai

Step-by-step explanation:

I promise I know why

7 0
3 years ago
Kelly earns $178.50 in interest on an account that earns simple interest at a rate of 4%. If she kept the money in the account f
Otrada [13]

Answer:

  $892.50

Step-by-step explanation:

The amount of interest earned is given by ...

  I = Prt

Filling in the given values, we have ...

  $178.50 = P·0.04·5

Dividing by 0.20 gives ...

  $178.50/0.20 = P = $892.50

The principal amount in Kelly's account is $892.50.

7 0
3 years ago
In which graph do all of thw indicated points have x-coordinates that satisfy x <-3
Helga [31]
You would have to choose a graph with all x coordinates equaling less than negative 3

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your answer is A :)
5 0
3 years ago
Read 2 more answers
A woman spent two thirds of her money she lost two thirds the remainder and then had $4 left how much money did she start with
Lisa [10]

Answer

Find out  how much money did she start with.

To proof

let us assume that the money she had be x.

As given

woman spent two thirds of her money

Money\ spent = \frac{2x}{3}

Money she had after spent two thirds of her money  = Total money - money spent

= x - \frac{2x}{3}

= \frac{1x}{3}

As given she lost two thirds the remainder

=\frac{2}{3}\times ( money\ she\ had\ after\ spending\ two\ thirds\ of\ her\ money)

= \frac{2}{3} \times\frac{1x}{3}

we get

=\frac{2x}{9}

Money she had after lost two thirds the remainder = Money she had after spent two thirds of her money - she lost two thirds the remainder

= \frac{1x}{3} - \frac{2x}{9}

= \frac{1x}{9}

As given

she had $4 left

thus

\frac{1x}{9} = 4

x = $36

she start with $36.

Hence proved

3 0
3 years ago
Read 2 more answers
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