“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.
Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.
Throw 3b into the first equation we have the new d as:
d = k • (3b)^2
Simplifying this, you have d = k•9b or d=9kb
This means the new braking distance is 9 times the original braking distance.
a pair of jenas that sell for $49
rate of tax is 6%
cost of that jeans is ?
Let the cost of jeans = x
through question
or, $49 = X + X×6%
or,$49 = X + X×6/100
or, $49 = 106X/100
or, $4900 = 106X
or, X = $4900/106
: X = $46.226
thus ; the cost of jeans is $46.226
Answer:
you will get 1/4
Step-by-step explanation:
2/2=1 and 8/2=4
I believe the answer is -9<span />
