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goldfiish [28.3K]
3 years ago
7

What percent does a lender generally look for when considering the debt-to-income (DTI) ratio of a loan applicant? a. Less than

or equal to 36% b. Less than or equal to 42% c. Less than or equal to 50% d. Less than or equal to 72%.
Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0

Dept to income (DTI) is the ratio which refers the percentage of the gross monthly income which is used to pay the monthly dept payment. The percentage  a lender generally look for when considering the debt-to-income (DTI) ratio of a loan applicant is less than or equal to 36 percent. Thus option A is the correct option.

<h3>Dept to income ratio</h3>

Dept to income (DTI) is the ratio which refers the percentage of the gross monthly income which is used to pay the monthly dept payment. Dept to income ratio is a measure of financial that compare the amount of dept to the overall income.

A lender generally look some of the following things for when considering the debt-to-income (DTI) ratio of a loan applicant-

  • Lender looks for a low dept-to-income because with small dept to income ratio can be successfully mange monthly payments.
  • Lender prefer to look a 36 percent or smaller dept-to-income with not more than 28 percent of that dept going towards servicing your mortgage.
  • Back end ratio must be no more than 36 percent(including all monthly dept) and front end ratio must be no more than 28 percent.

Hence the percentage  a lender generally look for when considering the debt-to-income (DTI) ratio of a loan applicant is less than or equal to 36 percent. Thus option A is the correct option.

Learn more about the dept to income ratio here;

brainly.com/question/16087693

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x=-4/3

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9x^2+12x+12x+16 this works just double checking

b)

16x^2 - 25y^2 =  0


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8 0
4 years ago
Solve each equation. check you solution.<br> (7t - 2) - (-3t + 1) = -3(1 - 3t)
Lynna [10]
(7t-2) - (-3t+1) = -3*(1-3t)
First distribute:
7t-2+3t-1 = -3+9t
Now get all the terms with 't' on the same side by subtracting/adding:
7t+3t-9t = -3+2+1
Combine the terms:
1t=0
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Check:
Plug in 0 for t and see if both sides of the equation come out the same:
Does (7(0)-2) - (-3(0)+1) = -3(1-3(0))  ?
(-2) - (1) = -3(1)  ?
-3 = -3  ?
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Please please help <br><br> Given the function f(x)=1/3x*2-3x+5 determine the inverse relation
yuradex [85]

The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)

<h3>How to determine the inverse relation?</h3>

The function is given as

f(x)=1/3x^2-3x+5

Start by rewriting the function in vertex form

f(x) = 1/3(x - 9/2)^2 -7/4

Rewrite the function as

y = 1/3(x - 9/2)^2 -7/4

Swap x and y

x = 1/3(y - 9/2)^2 -7/4

Add 7/4 to both sides

x + 7/4= 1/3(y - 9/2)^2

Multiply by 3

3x + 21/4= (y - 9/2)^2

Take the square roots

y - 9/2 = √(3x + 21/4)

This gives

y = 9/2 + √(3x + 21/4)

Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)

Read more about inverse functions at:

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2 years ago
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