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Mathematics

2 answers:

Art [367]3 years ago

8 0

Answer:

-7+4=-3

Step-by-step explanation:

Think of it as adding head to cold (cold being negative numbers). You are adding four "heats" to seven which makes it hotter. The hotter something gets the closer to positive numbers it is. . . so when adding four things if heat to 7 it gets hotter by four therefore it's now at -3.

sorry if that didn't make sense

vagabundo [1.1K]3 years ago

6 0

Answer & Step-by-step explanation:

To start the question, you could set up an equation to explain that -7 is being moved x units to -3

-7 + x = -3

Next you have to find x

-7 + x - (-7) = -3 - (-7)

x = 4

Now you substitute x for 4 in the original equation

-7 + 4 = -3

Hope this helped!!!

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kari74 [83]

The law of an object moving with constant acceleration is

$s(t)=s_0+v_0t+\dfrac{1}{2}at^2$

Where $s$ is space, $t$ is time, $s_0$ is the initial position, $v_0$ is the initial velocity and $a$ is the acceleration.

In this case, if we choose a reference grid with the vertical axis pointing upwards, the acceleration of gravity will point downwards (and thus be negative). The initial position is zero, because the rocket is on the ground, and the initial velocity is 100 (positive because pointing upwards).

So, its law is

$h(t)=100t-\dfrac{1}{2}gt^2$

(I changed $s$ for $h$ since the rocket is moving vertically, so its position is actually its height. Also, g is the acceleration due to gravity).

The rocket hits the ground if its height is zero, so if we set $h=0$ we have

$0=100t-\dfrac{1}{2}gt^2 \iff t(100-\dfrac{1}{2}gt)=0$

Solving for t, we have either t=0, or

$100-\dfrac{1}{2}gt=0 \iff 100=\dfrac{1}{2}gt \iff 200=gt \iff t=\dfrac{200}{g}$

The solution t=0 means that at the beginning the rocket is on the ground. So, we're interested in the other solution. Considering that g is about 32.2 feet/s^2, we have

$t=\dfrac{200}{g}\approx \dfrac{200}{32.2}\approx 6.21$