Oof, division rule:
(f/g)'=(f'g-fg')/g^2
Let (9t-8)^6=f and t+2=g
Thus we get
(9*6(9t-8)^5*(x+2)-(9t-8)^6)/(x+2)^2
(54(9t-8)^5*(x+2)-(9t-8)^6)/(x^2+4x+4)
I'm not sure how much I'm supposed to simplify this...
Answer:
x = ±1
Step-by-step explanation:
Step 1: Define variables
f(x) = x² + 1
f(x) = 2
Step 2: Substitute
2 = x² + 1
Step 3: Solve for <em>x</em>
0 = x² - 1
0 = (x - 1)(x + 1)
x - 1 = 0
x = 1
x + 1 = 0
x = -1
∴ x = ±1
Answer:
reflect
Step-by-step explanation:
dilate means bigger or smaller than the original.
