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snow_lady [41]
3 years ago
11

An olympic sprinter can go from a state of rest to 11 meters per second in 10 seconds. What is the sprinter's average accelerati

on?
Physics
2 answers:
Phoenix [80]3 years ago
7 0

Answer:  Sprinter's average acceleration =  1.1\frac{m}{s^2}

Explanation:

The formula for the average acceleration is given as follows:

\overline{a} = \frac{v_f - v_i}{\Delta t} --- (A)

Where,

v_f = Final velocity = 11\frac{m}{s}

v_i = Initial velocity = 0\frac{m}{s}

\Delta t = Elapsed time = 10 seconds

Plug the values in equation (A):

\overline{a} = \frac{11 - 0}{10} = 1.1\frac{m}{s^2}


Therefore, the sprinter's average acceleration is 1.1\frac{m}{s^2}.


Andrew [12]3 years ago
4 0
Since I think the formula for acceleration is a=d/t you plug in 11 for d and 10 for t and get 11/10=1.1 so 1.1 m/s is his/her acceleration.
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3 years ago
Salmon often jump waterfalls to reach their
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Answer:

5.0 m/s

Explanation:

The horizontal motion of the salmon is uniform, so the horizontal component of the salmon's velocity is constant and it is

v_x = u cos \theta

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d=v_x t = (ucos \theta)t

where d = 1.95 m and t is the time needed to reach the final point.

Re-arranging for t,

t=\frac{d}{v_x}=\frac{d}{u cos \theta} (1)

Along the vertical direction, the equation of motion is

y=h+u_y t -\frac{1}{2}gt^2

where:

y = 0.311 m is the final height reached by the salmon

h = 0 is the initial height

u_y = u sin \theta is the vertical component of the initial velocity of the salmon

g=9.81 m/s^2 is the acceleration of gravity

t is the time

Substituting t as found in eq.(1), we get the equation

y=(u sin \theta) \frac{d}{u cos \theta}- \frac{1}{2}g\frac{d^2}{u^2 cos^2 \theta}=d tan \theta - \frac{1}{2}g\frac{d^2}{u^2 cos^2 \theta}

and we can solve this formula for u, the initial speed of the salmon:

y=d tan \theta - \frac{1}{2}g\frac{d^2}{u^2 cos^2 \theta}\\\\u=\sqrt{\frac{gd^2}{2(dtan \theta -y)cos^2 \theta}}=\sqrt{\frac{(9.81)(1.95)^2}{2((1.95)(tan 37.7^{\circ}) -0.311)cos^2 37.7^{\circ}}}=5.0 m/s

5 0
4 years ago
A light with a second-order bright band forms a diffraction angle of 30. 0°. The diffraction grating has 250. 0 lines per mm. Wh
Luden [163]

The distance between two successive troughs or crests is known as the wavelength. The wavelength of the light will be 1000 nm.

How do you define wavelength?

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

Diffraction angle= 30⁰

Diffraction grating per mm= 250

wavelength = ?

Mathematically the equation of bright band is given by

\rm \lambda= \frac{sin\theta}{nN}

\rm \lambda= \frac{sin23^0}{250\times 2}

\rm \lambda= 0.000001 m

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Hence the wavelength of the light will be 1000 nm.

To learn more about the wavelength refer to the link;

brainly.com/question/7143261

8 0
2 years ago
Read 2 more answers
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