Answer:
The resultant vector is
.
Explanation:
First, each vector is determined in terms of absolute coordinates:
6-meter vector with direction: 30º north of east.


4-meter vector with direction: 30º east of north.


The resultant vector is obtaining by sum of components:

The resultant vector is
.
Answer:
Specific heat at constant pressure is = 1.005 kJ/kg.K
Specific heat at constant volume is = 0.718 kJ/kg.K
Explanation:
given data
temperature T1 = 50°C
temperature T2 = 80°C
solution
we know energy require to heat the air is express as
for constant pressure and volume
Q = m × c × ΔT ........................1
here m is mass of the gas and c is specific heat of the gas and Δ
T is change in temperature of the gas
here both Mass and temperature difference is equal and energy required is dependent on specific heat of air.
and here at constant pressure Specific heat is greater than the specific heat at constant volume,
so the amount of heat required to raise the temperature of one unit mass by one degree at constant pressure is
Specific heat at constant pressure is = 1.005 kJ/kg.K
and
Specific heat at constant volume is = 0.718 kJ/kg.K
Answer:
D. wood, hydrogen gas, milk, and water
Explanation:
Waves will transmit through wood, hydrogen gas, milk and water.
Waves are disturbances that propagates energy usually through a material medium.
Most mechanical waves pass through the given medium. Only electromagnetic waves do not really require a material medium for their propagation. They can be propagated through a vacuum.
Answer:
A) first laser
B) 0.08m
C) 0.64m
Explanation:
To find the position of the maximum you use the following formula:

m: order of the maximum
λ: wavelength
D: distance to the screen = 4.80m
d: distance between slits
A) for the first laser you use:

for the second laser:

hence, the first maximum of the first laser is closer to the central maximum.
B) The difference between the first maximum:

hence, the distance between the first maximum is 0.08m
C) you calculate the second maximum of laser 1:

and for the third minimum of laser 2:

Finally, you take the difference:

hence, the distance is 0.64m