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myrzilka [38]
2 years ago
11

Help!!! Asap!!!

Physics
1 answer:
KiRa [710]2 years ago
4 0

Answer:

Probs paper cuz the rest are metals

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A 25kg mass is suspended at the end of a horizontal, massless rope that extends from a wall on the left and from the end of a se
patriot [66]
<h2>Answer:20.97g N,32.63g N</h2>

Explanation:

We consider the forces at the knot.

The vertical forces are

T_{2}Sin(50^{0}}) is the vertical component of tension T_{2} at the knot.

-25g is the weight of the mass 25Kg acting downwards.

The horizontal forces are

-T_{1} is the tension in the rope acting left.

T_{2}Cos(50^{0}) is the horizontal component of tension T_{2} acting towards right.

Since the knot has no mass,it is always in equilibrium.

So,the sum of forces acting on it will be zero.

Balancing vertical forces gives,

T_{2}Sin(50^{0}})-25g=0

T_{2}=32.63gN

Balancing horizontal forces gives,

T_{2}Cos(50^{0})-T_{1}=0

T_{1}=32.63g\times Cos(50^{0})=20.97gN

7 0
3 years ago
Read 2 more answers
A coil spring stretches by 2.50 cm when a mass of 750 g is suspended from it. (a) Find the force constant of the spring. (b) How
weqwewe [10]

Answer:

(a) 294 N/m

(b) 0.027 m or 2.7 cm

Explanation:

(a) From Hook's law,

F = ke......................... Equation 1.

make k the subject of the equation

k = F/e..................... Equation 2

Where F = force applied on the spring, k = spring constant, e = extension.

From the question, the force applied to the spring is the weight of the mass.

F = mg = 0.75(9.8) = 7.35 N

Also, e = 2.5 cm = 0.025 m

Substitute these values into equation 2

k = 7.35/0.025

k = 294 N/m.

(b) If a mass of 800 g is suspended,

F = ke

e = F/k................... Equation 3

F = mg = 0.8(9.8) = 7.84 N,

k = 294 N/m.

Substitute these values into equation 3

e = 7.84/294

e = 0.027 m

e = 2.7 cm

7 0
3 years ago
In your own words, explain how stalagmites are formed in caves.
romanna [79]
Stalagmite formation occurs only under certain pH conditions within the cave. They form through deposition of calcium carbonate and other minerals
7 0
3 years ago
8. A car travels at a constant velocity of 70 mph for one hour. By the end of the second hour, the car’s velocity was 60 mph. At
Mrac [35]

<u>Answer:</u>

  Positive acceleration is in third hour and negative acceleration is in second hour.

<u>Explanation:</u>

  Velocity of car in first hour =  70 mph

  Velocity of car in second hour = 60 mph

  Velocity of car in third hour = 80 mph

   Acceleration = Change in velocity / Time

   Acceleration in second hour = (60 - 70)/1 = -10 mph²

   Acceleration in third hour = (80 - 60)/1 = 20 mph²

   So positive acceleration is in third hour and negative acceleration is in second hour.

8 0
4 years ago
A cyclist named Carly Daugherty accelerates from 0 m/s to 8 m/s in 3 seconds. What is her acceleration? Is this acceleration hig
Paraphin [41]

           Magnitude of acceleration =

                                     (change in speed) / (time for the change) .

Magnitude of Carly's acceleration =

                                                     (8 m/s) / (3 sec)  =  2-2/3 m/s²

Magnitude of Soul Train's acceleration =

                                                    (30 m/s) / (8 sec) = 3.75 m/s² .

Soul Train's acceleration is about 41% greater than Carly's.

7 0
3 years ago
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