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kotegsom [21]
3 years ago
12

Answer this please!!!!

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0

Answer:

Danielle spent 38.80 dollars over long distance

Step-by-step explanation:

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Action of Mixed Numbers
koban [17]

Answer:

-8 hours/week

Step-by-step explanation:

Erik = 4 hours/week

Little Brother = 12 hours/week

How many more hours does Eric ride his bike during the week than his little brother?

Erik - Little Brother = (4 hrs/wk - 12 hrs/wk)

Erik rides his bike -8 hours/week more than his little brother.

3 0
1 year ago
you roll a one die and flip a coin. what is the probability that you get heads with a number less than 3​
Aneli [31]

Answer:

sheeeesh thas hard is like is like ion even know man ahaha

6 0
3 years ago
Read 2 more answers
The area of a rectangle having breadth 2.6m is 18.33 sq.m. Find the<br> length of rectangle.
ladessa [460]

Answer:

Length = 7.05m

Step-by-step explanation:

Breadth is just a fancy word for width. We know that the width is 2.6 m and the total area is 18.33 m². We also know that the formula for the area of a rectangle is l*w, length times width. Remember, we are looking for l.

Set up an equation: l*w=A

Where:

  • l = Length
  • w = Width
  • A = Area

Plug in the known values.

l*w=A

l * 2.6 = 18.33

Solve for l. Isolate the variable by dividing both sides of the equation by 2.6:

l = 7.05

You can easily check your work by finding l*w now that you know both values. Always remember to put the unit back into your answer! So your final answer should be l=7.05 m

4 0
3 years ago
Please help its urgent:
Lelechka [254]

Answer:

  • 1/60

Step-by-step explanation:

<u>Permutations of "Panda"</u>

  • 5P5 = 5! = 120

<u>Two of the 'Panda" s we can get as a result</u>

  • P(Panda) = 2/120 = 1/60
6 0
3 years ago
A random sample is selected from a population with mean μ = 102 and standard deviation σ = 10. For which of the sample sizes wou
chubhunter [2.5K]

Answer:

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

Step-by-step explanation:

For this case we know that for a random variable X we have the following parameters given:

\mu = 102, \sigma =10

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

8 0
3 years ago
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