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3 years ago

Answer this please!!!!

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

4 0

Answer:

Danielle spent 38.80 dollars over long distance

Step-by-step explanation:

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A cable hangs between two poles of equal height and 3737 feet apart.

geniusboy [140]

Answer:

15450.4 pounds

Step-by-step explanation:

Given the distance between the poles is D = 3737 feet, and

f(x) = 10 + 0.1x^3/2

= 10 + 1/10 x^3/2

We need to find the arc length of the cable and this is given by:

L = integral of √(1 + [f'(x)]²) dx, between D=0 and D/2

Where f'(x) = d(f(x))/DX

f'(x) = 3/2 × 1/10x^1/2 = 3/20 √x

Hence, L = integral of (√(1 + [3/20√x]²))dx, between D=0 and D/2

L = integral(√(1 + (9/400)x))dx; D=0 and D/2

L = integral(√(1 +9x/400))dx; D=0 and D/2

Let u= 1+ (9x/400) ; du/dx = 9/400

dx = (400/9)du

L= integral (√u) × +(400/9)du; btw D=0 and D/2

L = (400/9) × integral (√u)du

L= (400/9) × (u^3/2)÷(3/2)

L = (800/27)[u^3/2]

Now we replace 1 + (9x/400)

and evaluate between D=0 and D/2 = 1868.5 ft

L= (800/27)[(1 + (9× 1868.5/400)-(1 + 0)]

L=( 800/27) × (9× 1868.5/400)

L = (800 27) × 42.04

L=1246 feet (approximately)

The weight = 12.4 × 1246

Weight = 15450.4 pounds

6 0

3 years ago

Assume that the sales of a certain appliance dealer can be approximaed y sraig were $6000 in 1982 and $ 64,000 in 1987. Let x -

viktelen [127]

Answer:

$y=11,600x+6,000$

Yearly sales in 1990: $98,800.

Step-by-step explanation:

We have been given that the sales of a certain appliance dealer can be approximated by a straight line. Sales were $6000 in 1982 and $ 64,000 in 1987.

If at 1982, $x=0$ then at 1987 x will be 5.

Now, we have two points (0,6000) and (5,64000).

$\text{Slope}=\frac{64,000-6,000}{5-0}$

$\text{Slope}=\frac{58,000}{5}$

$\text{Slope}=11,600$

Now, we will represent this information in slope-intercept form of equation.

$y=mx+b$ , where,

m = Slope,

b = Initial value or y-intercept.

We have been given that at $x=0$ , the value of y is 6,000, so it will be y-intercept.

Substitute values:

$y=11,600x+6,000$

Therefore, the equation $S=11,600x+6,000$ represents yearly sales.

Now, we will find difference between 1990 and 1982.

$1990-1982=8$

To find yearly sales in 1990, we will substitute $x=8$ in the equation.

$S=11,600(8)+6,000$

$S=92,800+6,000$

$S=98,800$

Therefore, the yearly sales in 1990 would be $98,800.

6 0

3 years ago

Give the radian measure of an angle drawn in standard position that corresponds with the ray containing the coordinate point (−1

Sergeu [11.5K]

Answer:

The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point $(-12, -3\sqrt{2})$ is approximately $1.108\pi$ radians.

Step-by-step explanation:

With respect to origin, the coordinate point belongs to the third quadrant, which comprises the family of angles from $\pi\,rad$ to $\frac{3\pi}{2}\,rad$ . The angle in standard position can be estimated by using the following equivalence:

$\theta = \pi\,rad + \tan^{-1} \left(\frac{3\sqrt{2}}{12} \right)$

$\theta \approx \pi \,rad + 0.108\pi \,rad$

$\theta \approx 1.108\pi\,rad$

The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point $(-12, -3\sqrt{2})$ is approximately $1.108\pi$ radians.

5 0

3 years ago

Subtract the cube root of the product of h and 3k from the square of the sum of p and q

ehidna [41]

Answer:

(p + q)² - ∛(h·3k) or (p + q)² - ∛(h·3k)

Step-by-step explanation:

Cube root of x: ∛x

Product of h and 3k: h·3k

Sum of p and q: p + q

*****************************

From (p + q)² subtract ∛(h·3k) This becomes, symbolically:

=> (p + q)² - ∛(h·3k)

3 0

3 years ago

A sequence of numbers in which the ratio between any two consecutive numbers is a constant is called a(n):

Anestetic [448]

It is called a geometric sequence

6 0

3 years ago

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