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Luden [163]
2 years ago
6

In a recent town election, 1,860 people voted for either candidate A or candidate B for the position of supervisor.

Mathematics
1 answer:
Lera25 [3.4K]2 years ago
4 0
837.

EXPLANATION:

if candidate A recieved 55% of the votes,

Then candidate B recieved 45% of the votes, because it must equal 100%

45% of 1860 is 837.

Hope this helpz!
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So I don't understand how V = lwh (h).... the topic is literal equations.
Kruka [31]

1) Solving in terms of h

V = lwh <em>Divide both sides by h</em>

<em />

\begin{gathered} V\text{ = lwh} \\ \frac{V}{h}=\frac{lwh}{h} \\ \frac{V}{h}\text{ =}lw\text{ Cross multiply} \\ hlw=V\text{ Divide both sides by lw} \\ \frac{hlw}{lw}=\text{ }\frac{V}{lw} \\ h\text{ = }\frac{V}{lw} \end{gathered}

So rearranging that equation we can find h, in terms of V, and l and w.

If we want to solve in terms of l, or w, we'll proceed similarly to isolate the variable we want on the left side, and the other terms on the right side.

6 0
1 year ago
-7÷x=19<br><br>need your help​
RSB [31]

Answer:

the answer is 26

Step-by-step explanation:

you add 7 to -7 and 19. the positive and negative 7 cancels each other out. them you add 19 and 7 which is 26. that means x is 26.

btw watch hameltion its on diesny plus its the best musical ever, just give it a try.

8 0
2 years ago
What's the answer for 3/4 (x+3)=9
Vitek1552 [10]
We want to solve the equation :

\displaystyle{  \frac{3}{4}(x+3)=9


first, multiply both sides by 4:

\displaystyle{ \cancel{4} \cdot \frac{3}{ \cancel 4 }(x+3)=4\cdot 9

\displaystyle{ 3(x+3)=36


divide both sides by 3:

x+3=12


add -3 to both sides:

x=9



Answer: x=9
3 0
3 years ago
Math help please, thx
pogonyaev
The answer is radical 9
5 0
3 years ago
Graph x &gt; 2
Andrews [41]

Answer:

Bottom left

Step-by-step explanation:

Because when you draw the graph you see that x is larger than 2 , and 2 is not including in the solution so, we just make a small lines (forget the y-axis).

I hope that it's a clear solution and explanation.

3 0
3 years ago
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