For this case we have the following vector:
v = (- 8, 2)
Using product point we have:
v.v = (-8, 2). (- 8, 2)
v ^ 2 = (-8) * (- 8) + (2) * (2)
v ^ 2 = 64 + 4
v ^ 2 = 68
v = root (68)
v = root (4 * 17)
v = 2 * root (17)
Answer:
v = 2 * root (17)
option c
Answer:
I’m not sure, but I think he practiced before them?
Answer:
Step-by-step explanation:
Suppose the cost C(x), to build a football stadium of x thousand square feet is approximated by C(x) = 7,250,000/x + 60. Given the function, we can substitute values for x to determine the cost of a particular size of stadium or we can substitute values for C(x) to determine the number of square feet.
if the cost of the stadium was $8,000, the, we would determine the size of the stadium, x by substituting x $8,000 for C(x). It becomes
8000 = 7250,000/x + 60
8000 - 60 = 7250000/x
7940 = 7250000/x
7940x = 7250000
x = 7250000/ 7940
x = 913 ft^2
Answer:
<u>Step-by-step explanation:</u>
y = A cos (Bx - C) + D
- A = amplitude (vertical stretch)
- Period = 2π/B
- C/B = phase shift
- D = vertical shift
The minimum is -7 and the max is 7 so A = 7 and D = 0
Period is 7. Since P = 2π/B then 7 = 2π/B --> B = 2π/7
Nothing was stated about a phase shift so you can use any value for C. I chose C = 0.
Now, input A = 7, B = 2π/7, C = 0, & D = 0 into the equation
HIII~
There are 6 ways we can roll doubles out of a possible 36 rolls (6 x 6), for a probability of 6/36, or 1/6, on any roll of two fair dice
-Koko
I hope I helped!