A
Volume of the Cylinder
Givens
H = 60 yards.
Diameter = 20 yards
pi = 3.14
Formula
V = pi * r^2 * h
Calculations
r = d/2
r = 32/2
r = 16
V = 3.14 * 16^2 * 60
V = 48230 cubic yards [Cylinder's Volume]
Cone
<em>Formula</em>
V = 1/3 pi r^2 H
<em>Givens</em>
pi = 3.14
r = 16 yards
h = 20 yards
<em>Sub and solve</em>
V = 1/3 3.14 * 16^2 * 20
V = 5359 cubic yards.
<em>Total Volume of the structure</em>
48230 + 5359 = 53589 Cubic Yards
<em>Water Content</em>
The answer to this part requires a proportion.
1 Cubic yard will hold 201.97 gallons.
53589 yd^3 = x
1/201.97 = 53589 /x [ You should get a pretty big answer]
x = 201.87 * 53589
x = 10 819 092 gallons can be held by the tank.
10 819 092 gallons <<<< answer
B
If the height of both the cylinder and the cone remain the same. If the radius doubles in both the cylinder and the cone then the tank will hold 4 times as much.
Total volume before doubling the radius = pi * r^2 h + 1/3 pi r^2 h
New Total Volume = pi * (2*r)^2 h + 1/3 pi * (2r)^2 h
New Total volume = pi * 4r^2 h + 1/3 pi *4 r^2 h
New Total Volume = 4 [pi r^2 h + 1/3 pi r^2 h]
but pi r^2 h + 1/3 pi r^2 h is the total volume before doubling the radius
New volume = 4 original volume. <<<<< answer to part B
Answer: 37
Step-by-step explanation:
Well DCB is a right angle, and there is already half which is 53 degrees, subtract 90 by 53 and you will get your answer.
If you would like to solve p = r - c for c, you can do this using the following steps:
p = r - c /+c
p + c = r - c + c
p + c = r /-p
p + c - p = r - p
c = r - p
The correct result would be c = r - p.
25 = 5*5
405 = 81*5
therefore, 25/405 = (5*5)/(81*5)=5/81
The answer
X'Y' and XY are parallels, measX'Y'T = measXYT, there is similarity between the two triangles, we can find YT by using theorem of thales,
it is TY' / TY =TX' / TX =X'Y' /XY, so TY' / TY = TX' / TX = 9/ TY =6/ 2+6=6/8
and then 9/ TY = 6/8 therefore TY= 12
