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1 year ago

The polygons are similar. The area of one polygon is given. Find the area of the other polygon.

Mathematics

1 answer:

Fantom [35]1 year ago

5 0

Answer:

108 ft²

Step-by-step explanation:

For the polygon on the left, we are given the length of one side (3 ft) and the total area (27 ft²). With this information, we can determine the length of the other side - 9 ft. I found this by dividing 27 ft² by 3 ft, giving me the final result of 9 ft.

Next, we have to find the other side of the polygon on the right so we can ultimately determine its area. It looks like there is a scale factor of 2 between the two polygons, since 3 × 2 = 6. We know that the bottom side of the left polygon is 9, so multiplying 9 by 2 should give us the bottom side of the polygon on the right. 9 × 2 = 18.

Now, we have the side lengths for the polygon on the right and can determine its area. What is 6 ft × 18 ft? Well, the answer is 107 ft², and this is the answer to the question.

Hopefully that's helpful! :)

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The measurement, y, varies directly with regard to another value, x. If y = 9 and x = 24, find x for y = 25. 9.4 50 66.7

ale4655 [162]

Answer:

The correct answer is C. 66.7

Step-by-step explanation:

1. y varies directly with regard to x

y = 9 and x = 24

If y = 25, what is the value of x?

2. For finding that value of x, first of all, we should understand what happened to y.

If y moves from 9 to 25 it means that y has been multiplied by 2.77, using this simple division

25/9 = 2.777

3. And we should use that same number or value to calculate the new value of x

If x was 24, now the new value of x is 24 * 2.777

24 * 2.777 = 66. 67 or 66.7 (rounding to just one decimal)

The correct answer is C. 66.7

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2 years ago

C-7.6=-4 what is the value of c

9966 [12]

C - 7.6 = -4
c = -4 + 7.6
c = 3.6

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2 years ago

Read 2 more answers

What is 1/4 of £42 and what is 2/5 of £13.50

xxTIMURxx [149]

Divide 42 by 4 for one fourth. Divide 13.5 by 5 and multiply that by 2.

5 0

3 years ago

Read 2 more answers

1. Find the sum of the measures of the interior angles of a convex 11-gon.

OleMash [197]

Answer:

The measure of the sum of interior angles of a 11-gon is $1620^{o}$ .

Each interior angle is approximately $147.273^{o}$ .

Step-by-step explanation:

A convex polygon has the measure of each interior angles to be less than $180^{o}$ .

But,

sum of interior angles of polygon = (n - 2) x $180^{o}$

where n is the number of sides of the polygon.

For a convex 11-gon, we have;

sum of angles of a 11-gon = (11 - 2) x $180^{o}$

= 9 x $180^{o}$

= $1620^{o}$

Sum of angles of a 11-gon = $1620^{o}$

To check: convex polygons' interior angles are less than $180^{o}$ .

so that,

each interior angle of 11-gon = $\frac{1620}{11}$

= $147.273^{o}$

3 0

2 years ago

Charlie's garage has a rectangular floor space. Its length is 3 times its width. Charlie extends the width of his garage to 6 m,

MAXImum [283]

Answer:

The percentage change is 140%

Step-by-step explanation:

Given

$L= 3W_1$ ---- initial dimension

$W_2 = 6m$ --- new width

$A_2 = 45m^2$ --- new dimension

Required

The percentage increment

The length remains constant because only the width is extended.

The new area is:

$Area =Length * Width$

$A_2=L * W_2$

Make L the subject

$L = \frac{A_2}{ W_2}$

Substitute values for A and W

$L = \frac{45m^2}{6m}$

$L = \frac{45m}{6}$

$L = 7.5m$ --- this is the length of the garden

Calculate the initial width:

$L= 3W_1$

Make W1 the subject

$W_1 = \frac{1}{3} * L$

$W_1 = \frac{1}{3} * 7.5$

$W_1 = 2.5$

So, the initial area is:

$A_1 = L_1 * W_1$

$A_1 = 2.5 * 7.5$

$A_1 = 18.75$

The percentage change in area is:

$\%A = \frac{A_2 - A_1}{A_1}$

$\%A = \frac{45 - 18.75}{18.75}$

$\%A = \frac{26.25}{18.75}$

$\%A = 1.4$

Express as percentage

$\%A = 1.4*100\%$

$\%A = 140\%$

4 0

2 years ago