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rewona [7]
1 year ago
9

Aaron flips a coin three times, what is the correct sample space (all possible outcomes)?

Mathematics
1 answer:
Vlada [557]1 year ago
6 0

HHH, HHT, HTH, THH, TTH, THT, HTT, TTT

That is representative of all possible outcomes from flipping the coin

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Suppose that a department contains 7 men and 15 women. How many ways are there to form a committee with six members if it must h
Anna [14]

Answer:

7502040

Step-by-step explanation:

you can have 6 women,5 women and 1 men,4 women and 2 men,

in first case,you can place women in 15*14*13*12*11*10 ways

in second case

15*14*13*12*11*7

and in third case

15*14*13*12*7*6

and you need to sum all this numbers

3 0
2 years ago
Planes X and Y are perpendicular. Points A, E, F, and G are points only in plane X. Points R and S are points in both planes X a
marusya05 [52]

Answer:

Planes EA and FG

Step-by-step explanation:

3 0
3 years ago
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
Does the graph f(x)=-2x^2 -1 have a maximum or a minimum? Explain.
Serga [27]

Answer:

It has a maximum

Step-by-step explanation:

The way I think about it is looking at "a" (the leading variable's coefficient, so __x²), if it's negative, the graph is a frown, but if it's positive, it's a smile. In this case, a is -2, so the graph would have the shape of a frown, which has a maximum.

I hope this helped!

8 0
3 years ago
ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.
fomenos

Answer:

C. The graph of G(x) is the graph of F(x) flipped over the y-axis and compressed vertically.

Step-by-step explanation:

The negative in front of the 2 made the function flip over the y-axis. While the 2, compressed the function a little, making it so the function touched 2, vertically.

7 0
2 years ago
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