Tags are attached to the left and right hind legs of a cow in a pasture. Let A1 be the event that the left tag is lost and the e
1 answer:
Answer:
Step-by-step explanation:
Given that tags are attached to the left and right hind legs of a cow in a pasture. Let A1 be the event that the left tag is lost and the event that the right leg tag is lost. Suppose those two events are independent and A2 the event that the right leg tag is lost. Suppose those two events are independent and P(A1) = P(A2) = 0.3
a) the probability that at least one leg tag is lost
=
(since A1 and A2 are independent)
=0.3+0.3-0.09
=0.51
b) the probability that exactly one tag is lost, given that at least one tag is lost.
= P(one leg lost)/P(atleast one leg lost)
=
c) the probability that exactly one tag is lost, given that at most one tag is lost.
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Answer:
a₈ = 37
Step-by-step explanation:
The given arithmetic sequence is: 3, 8, 13, 18, 23, . . .
The recursive formula for the sequence is:
Here, represents the
of the sequence.
And, represents the
of the sequence.
'+5' denotes that '5' is added to the term to get the
term. In other words, the difference between two consecutive numbers in the sequence is 5.
Now, we are asked to find a₈ i.e., n =8.
Substituting in the recursive formula we get: a₈ = a₍₈₋ ₁₎ + 5 = a₇ + 5.
So, to determine a₈ we need to know a₇. From the sequence we see that a₅ = 23.
⇒ a₆ = 23 + 5 = 28.
⇒ a₇ = 28 + 5 = 32.
⇒ a₈ = 32 + 5 = 37.
Therefore, the term of the sequence is 37.