Given:
Volume of cuboid container = 2 litres
The container has a square base.
Its height is double the length of each edge on its base.
To find:
The height of the container.
Solution:
We know that,
1 litre = 1000 cubic cm
2 litre = 2000 cubic cm
Let x be the length of each edge on its base. Then the height of the container is:
The volume of a cuboid is:
Where, l is length, w is width and h is height.
Putting 
, we get
Divide both sides by 2.
Taking cube root on both sides.
![\sqrt[3]{1000}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1000%7D%3Dx)
Now, the height of the container is:
Therefore, the height of the container is 20 cm.
In our equation, the Y value is the dependent variable and the X is the independent variable. The amount of pounds lost depends on the number weeks on a diet. To get the actual pounds Steve was able to lose in 4 weeks, we have:
Y = 1.8x + 1.2
Y = 1.8(4) + 1.2
Y = 8.4 pounds
Answer:
6.50+0.70t
Step-by-step explanation:
Answer:
{f, a}
Step-by-step explanation:
Given the sets:
X = {d, c, f, a}
Y = {d, e, c}
Z ={e, c, b, f, g}
U = {a, b, c, d, e, f, g}
To obtain the set X n (X - Y)
We first obtain :
(X - Y) :
The elements in X that are not in Y
(X - Y) = {f, a}
X n (X - Y) :
X = {d, c, f, a} intersection
(X - Y) = {f, a}
X n (X - Y) = elements in X and (X - Y)
X n (X - Y) = {f, a}
