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san4es73 [151]
3 years ago
13

Find the area of a triangle with vertices (1, 5), (1, -2), (3,-2).

Mathematics
1 answer:
ollegr [7]3 years ago
3 0

Answer:

Step-by-step explanation:

A(3, - 2), B(1, 5), C(1, - 2)

ΔABC is right angled Δ

AC and BC are legs (cathetus)

A_{ABC} = (AC)(BC) ÷ 2 = \frac{2*7}{2} = 7 units²

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7 0
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Read 2 more answers
Hi, having trouble understanding this question.. as well as solving it.
kramer

-- You have two angles.

-- They're complementary . . . they add up to 90 degrees.

-- One is 4 times as big as the other one.
___________________________________________

-- The smaller angle has 1 share of the 90 degrees.

-- The bigger angle has 4 shares of the 90 degrees.

-- (The smaller one is 1/4 the size of the bigger one.
   The bigger one is 4 times the size of the smaller one.)

-- When you add them together, you get 5 shares, totaling 90 degrees.

-- What's the size of each share ?  It's 90/5 = 18 degrees.

-- The smaller angle gets one share . . . 18 degrees.

-- The bigger angle gets 4 shares.   (4 x 18) = 72 degrees.
____________________________________

Check:

-- Is the small one 1/4 the size of the big one ?    18/72 = 1/4  Yes.

-- Are they complementary ?  Do they add up to 90 degrees ?

                                                                       18 + 72  =  90  Yes.

                                                                                 yay !
6 0
3 years ago
Read 2 more answers
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