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JulsSmile [24]
4 years ago
15

Pls it’s urgent my homework is due tomorrow PLS HELP

Mathematics
1 answer:
kramer4 years ago
4 0

Answer:

i) x= -0.25, x=1.25

ii)x=1.5, x= -0.5     (notice the negative signs)

Step-by-step explanation:

So, to simply solve this(or estimate), notice what the equations say at the end of them!

0 and 2, and also notice the equations are exactly the same as the graph's.

This means, by substitution, we are look for the x-values at y=0, and at y=2

(because they are exactly the same, in those instances, we can just replace the equation with the value of 0, or 2 because they are equal)

Then all we have to do is imagine the lines of y=0(x-axis) and y=2, and find where the parabola intersects those lines.

And so, just find where they intersect, and you have got it!

Hope this helps!

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Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?
serious [3.7K]

Answer:

c) 6x + y = -52  is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form    : y = mx  + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 :  -x + 6y = -12

or, 6y = -12  + x

or, y = (x/6)  - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2  to be  perpendicular:

Check for each equation:

a. x + 6y = -67       ⇒  6y = -67  - x

or, y = (-x/6)  - (67/6)      ⇒Slope of line 2 = (-1/6)

but \frac{1}{6} \times \frac{-1}{6}  \neq -1

b. x - 6y = -52   ⇒  -6y = -52  - x

or, y = (x/6)  + (52/6)      ⇒Slope of line 2 = (1/6)

but \frac{1}{6} \times \frac{1}{6}  \neq -1

c. 6x + y = -52    

or, y =y = -52  - 6x      ⇒Slope of line 2 = (-6)

\frac{1}{6} \times (-6)  =  -1

Hence, 6x + y = -52  is required equation 2.

d. 6x - y = 52  ⇒  -y = 52  - 6x

or, y = 6x   - 52      ⇒Slope of line 2 = (6)

but \frac{1}{6} \times 6  \neq -1

Hence,  6x + y = -52  is  the  only required equation .

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Answer:

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Answer:

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Step-by-step explanation:

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