Answer:
see several wrong answers posted (and one correct answer so far), so I will try to present the correct solution.
Total number of possibilities is 36 (6 x 6), two six sided dice.
Of these possibilities, 21 are greater than 6, listed here: 6 ways to roll a 7, 5 ways to roll an 8, 4 ways to roll a 9, 3 ways to roll a 10, 2 ways to roll an 11, and 1 way to roll a 12.
These are the qualifying rolls: (1,6),(2,5),(2,6),(3,4),(3,5),(3,6),(4,3),(4,4),(4,5),(4,6),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6) - 21 total sums over 6
So the probability is 21/36, or simplifying, 7/12. Converted to a percentage, it is 58.333%.
