There are 25 species of trees, each with a known abundances. The question is how many possible ways to randomly select one tree there are.
We should calculate the number of combinations. Combinations, because we select item/s from a collection. In this case, when we select only one item, the combination is also a permutation. From set of n objects we select r. In our case: n=25, r=1.
The equation is: n!/r!(n-r)!= 25!/1!*24!=25*24!/24!=25
There are 25 different outcomes (events).
9514 1404 393
Answer:
8x -24 = 9y
Step-by-step explanation:
We assume your equation is ...
2/3x -2 = 3/4y
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Fractions can be eliminated by multiplying the equation by the least common denominator of the fractions.
LCM(3, 4) = 12
Multiplying the equation by 12 gives you ...
12(2/3x -2) = 12(3/4y)
8x -24 = 9y
Answer:
the independent variable in this equation is a because its the answer and cannot be changed
Answer:
? = 55
Step-by-step explanation:
if we put the triangles onto of each other
side CT is on top of TR
126 ÷ 70 = 1.8
70 × 1.8 = 126
BT is on top of TS
so,
99 ÷ ? = 1.8
99 = 1.8 × ?
99 ÷ 1.8 = ?
55 = ?
55 × 1.8 = 99
Hoped i helped :)