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m_a_m_a [10]
3 years ago
8

A boundary stripe 6 in. wide is painted around a rectangle whose dimensions are 120 ft by 230 ft. Use differentials to approxima

te the number of square feet of paint in the stripe.
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
7 0

Answer:

350 square feet

Step-by-step explanation:

We are given that

Width of strip=6 in

Dimension of rectangle=20 ft\times 230 ft

We know that

Area  of rectangle ,A=xy

Differentiate

dA=\frac{\partial A}{\partial x}x+\frac{\partial A}{\partial y}y

We have \frac{\partial A}{\partial x}=y=230 ft

\frac{\partial A}{\partial y}=x=120

dx=\frac{12}{12}=1 ft

1 ft=12 in

Because 6 in added in both side of breadth

dy=\frac{12}{12}=1 ft

Because 6 in added on both sides of length of rectangle

Substitute the values

dA=230\times 1+120\times 1=350 ft^2

Hence, the number of square feet of paint in the strip=350 square feet

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In the Central Grand Prix, out of 30 cars that started the race, 12 of them finished. What percent of the cars finished the race
zvonat [6]

Answer:

40% finished, which means that 60% did not.

Step-by-step explanation:

a = p*w

12 = p*30

12/30=p

.40 = p

40%

6 0
3 years ago
Please complete z2+9z-90=(z-6)(z+?) ...?
notka56 [123]
The answer is:  (z - 6)(z + 15)

z² + 9z - 90 = z*z + 15z - 6z - 6*15 =
                    = (z*z + 15z) - (6z + 6*15) = 
                    = z(z + 15) - 6(z + 15) =
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4 0
3 years ago
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Multiply: (5.8 x 10^-6) x (2 x 10^4).
Nitella [24]

Answer:

1.16*10^{-1}

Step-by-step explanation:

(5.8*10^{-6}) *(2*10^{4})\\=11.6*10^{-2}\\=1.16*10^{-1}

6 0
3 years ago
George and Maria decided to create a garden in their backyard. George Works on the garden every third day and Maria works on the
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The LCM of 3 and 4 is 12
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5(t - 3) -2t = -30 what is the answer?
maxonik [38]

Answer:

t = -5

Step-by-step explanation:

Solve for t:

5 (t - 3) - 2 t = -30

Hint: | Distribute 5 over t - 3.

5 (t - 3) = 5 t - 15:

5 t - 15 - 2 t = -30

Hint: | Group like terms in 5 t - 2 t - 15.

Grouping like terms, 5 t - 2 t - 15 = (5 t - 2 t) - 15:

(5 t - 2 t) - 15 = -30

Hint: | Combine like terms in 5 t - 2 t.

5 t - 2 t = 3 t:

3 t - 15 = -30

Hint: | Isolate terms with t to the left hand side.

Add 15 to both sides:

3 t + (15 - 15) = 15 - 30

Hint: | Look for the difference of two identical terms.

15 - 15 = 0:

3 t = 15 - 30

Hint: | Evaluate 15 - 30.

15 - 30 = -15:

3 t = -15

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 3 t = -15 by 3:

(3 t)/3 = (-15)/3

Hint: | Any nonzero number divided by itself is one.

3/3 = 1:

t = (-15)/3

Hint: | Reduce (-15)/3 to lowest terms. Start by finding the GCD of -15 and 3.

The gcd of -15 and 3 is 3, so (-15)/3 = (3 (-5))/(3×1) = 3/3×-5 = -5:

Answer: t = -5

5 0
3 years ago
Read 2 more answers
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