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damaskus [11]
2 years ago
10

GIVING 15 POINTS!!!! Solve the questions that are presented in the picture

Mathematics
2 answers:
dybincka [34]2 years ago
4 0
It is 1/6 because if you calculate it it gives you the answer
DanielleElmas [232]2 years ago
4 0
The answer is 1/6 you welcome
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Which of the following equations has the given solution set?
tester [92]
-2m + 5 = 2m + 5
2m + 2m = 5 - 5
4m = 0
m = 0

-2m + 5 = -2m + 5
-2m + 2m = 5 - 5
0 = 0

-2m + 5 = -2m - 5
-2m + 2m = 5 + 5
0 = 10
Solution set is Ф
The third equation is the correct answer.
8 0
3 years ago
How many cups is 15 pints
Keith_Richards [23]

1 pint = 2 cups
2 pints = 4 cups
3 pints = 6 cups
4 pints = 8 cups
5 pints = 10 cups
6 pints = 12 cups
7 pints = 14 cups
8 pints = 16 cups
9 pints = 18 cups
10 pints = 20 cups
11 pints = 22 cups
12 pints = 24 cups
13 pints = 26 cups
14 pints = 28 cups
15 pints = 30 cups

3 0
3 years ago
Read 2 more answers
Kevin weighed his loaded truck at a weigh station. It weighed 14 tons 500 lbs 9 oz. His empty truck weighed 2 tons 600 lbs 12 oz
LenaWriter [7]
None of these are correct my calculations are 11 tons 2138 Ibs 28 oz
7 0
3 years ago
You calculated probabilities involving various blood types. Some of your answers depended on the assumption that the outcomes de
Natali5045456 [20]

Answer:

a) The events are disjoint, because a person cannot have blood type A and blood type B at the same time.

b) The events are independent, because the probability of having blood type does not depend on other persod having blood type B.

c) Yes, disjoint events are independent if and only if the probability of some of the events is zero.

Step-by-step explanation:

a) Let the events be:

A: "the person has blood type A

B: the person has blood type B

As a person can only have one blood type these events are disjoint.

b) If we examine two people, let the events be that the first is blood Type A and the second blood Type B:

The events are independent because the probability of the first person having blood type A does not influence the probability of the second person having blood type B (unless the two people are related).

c) Two events are independent if and only if:

P(A∩B)=P(A)×P(B)

Given the events A and B which are disjoint:

P(A∩B)=0

Hence, A and B could be independent events if and only if the probability of one of the events is 0.

3 0
3 years ago
I don’t know how to do this can someone please help
PolarNik [594]
I believe it would be -16k^3 + 3v^4 - 9k^3 + 6v^4
7 0
3 years ago
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