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3 years ago

Help Please! Find The Missing Sides Using Special Right Triangles.

Mathematics

1 answer:

matrenka [14]3 years ago

6 0

Answer:

Choice 1

Step-by-step explanation:

m^2 +n^2=13^2

m^2=13^2-n^2

n^2=13^2-m^2

Both m & n =(13 x sq rt 2)/2

To put it another way:

m=(sq rt 2)/2 x 13

n=(sq rt 2)/2 x 13

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You are given the following information: Stockholders' equity = $323 million; price/earnings ratio = 14; shares outstanding = 8,

vagabundo [1.1K]

Answer:

$282.59 per share

Step-by-step explanation:

Given that,

Stockholders' equity = $323 million

price/earnings ratio = 14

shares outstanding = 8,800,000

Market/book ratio =7.7

Book Value per share:

= Stockholders' equity ÷ shares outstanding

= $323,000,000 ÷ 8,800,000

= $36.70

Market price per share:

= Book Value per share × Market/book ratio

= $36.70 × 7.7

= $282.59 per share

3 0

3 years ago

Someone plz help me T^T

IRINA_888 [86]

Answer:24 red 48 yellow and 24 white.

Step-by-step explanation:

Math

8 0

3 years ago

Will give brainliest! N/2+25 = 375 N = ? (n/2 is a fraction)

Art [367]

Solve for N by simplifying both sides of the equation, then isolating the variable.

N=700

Hope this helps, if not, comment below please!!!

7 0

3 years ago

Read 2 more answers

If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure & the perimeter of triangle ABC.

harina [27]

Answer:

$Perimeter = 38.6$

Step-by-step explanation:

Given

$A\ B = 13$

$B\ F = 9$

$F\ C = 5.6$

Required

Calculate the perimeter of A B C

To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

$Perimeter = A B + B\ C + A\ C$

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

$B\ C^2 = B\ F^2 + F\ C^2$

Substitute values for BF and FC;

$B\ C^2 = 9^2 + 5.6^2$

$B\ C^2 = 81 + 31.36$

$B\ C^2 = 112.36$

$B\ C^2= \sqrt{112.36$

$B\ C = 10.6$

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

$A\ B^2 = B\ F^2 + A\ F^2$

Substitute values for B F and A B;

$13^2 = 9^2 + A\ F^2$

$169= 81 + A\ F^2$

$A\ F^2 = 169 - 81$

$A\ F^2 = 88$

$A\ F = \sqrt{88$

$A\ F = 9.4$

Since F lies on line A C:

$A\ C = A\ F + F\ C$

$A\ C = 9.4 + 5.6$

$A\ C = 15.0$

Recall that:

$Perimeter = A\ B + B\ C + A\ C$

$Perimeter = 13 + 10.6 + 15.0$

$Perimeter = 38.6$

Hence, the perimeter is 38.6

3 0

3 years ago

A fisherman leaves his home port and heads in the direction N 70 ° W. He travels d1 = 40 mi and reaches Egg Island. The next day

Gnesinka [82]

Answer:

A)82.02 mi

B) 18.7° SE

Step-by-step explanation:

From the image attached, we can see the angles and distance depicted as given in the question. Using parallel angles, we have been able to establish that the internal angle at egg island is 100°.

A) Thus, we can find the distance between the home port and forrest island using law of cosines which is that;

a² = b² + c² - 2bc Cos A

Thus, let the distance between the home port and forrest island be x.

So,

x² = 40² + 65² - 2(40 × 65)cos 100

x² = 1600 + 4225 - (2 × 2600 × -0.1736)

x² = 6727.72

x = √6727.72

x = 82.02 mi

B) To find the bearing from Forrest Island back to his home port, we will make use of law of sines which is that;

A/sinA = b/sinB = c/sinC

82.02/sin 100 = 40/sinθ

Cross multiply to get;

sinθ = (40 × sin 100)/82.02

sin θ = 0.4803

θ = sin^(-1) 0.4803

θ = 28.7°

From the diagram we can see that from parallel angles, 10° is part of the total angle θ.

Thus, the bearing from Forrest Island back to his home port is;

28.7 - 10 = 18.7° SE

4 0

3 years ago