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masya89 [10]
4 years ago
7

Create a Punnett Square to illustrate the probability of a black rabbit if a white male were mated with a black female. Use W fo

r white, which is dominant, and b for black, which is recessive (hint: create a Punnett Square for a homozygous white male and a heterozygous white male).

Biology
2 answers:
Slav-nsk [51]4 years ago
6 0

There you go!! The Pheno type is 100% white male and Genotype is 100% Wb

Vesnalui [34]4 years ago
5 0

Answer:

0%

Explanation:

Allele for white colour is represeted by w.

Allele for black colour is represented by b.

b allele is recessive to w allele.

Homozygous white rabbit will have the genotype ww.

Heterozygous white rabbit will have the genotype wb.

Crossing ww and wb:

ww  x   wb  = ww, wb, ww, and wb

Since w is dominant over b, it means all of the offspring are white with 50% being homozygous and 50% being heterozygous.

<em>The probability of a black rabbit offspring is 0%.</em>

<em>See the image for the Punnet square analysis.</em>

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Identify the phenotypes for the offspring of a parent with the genotype IBi and a parent with the genotype IAIA. type O type A,
agasfer [191]
 <span>I is dominant, i is recessive. The A's and B's are just show which allele I is. When there is just one dominant allele, it masks the recessive in blood typing. Remember IA and IB are codominant. 

O is always ii 
A is IAi (heterozygous) or IAIA (homozygous) 
B is IBi (heterozygous) or IBIB (homozygous) 
AB is always IAIB 

Remember: You get one allele from each parent! 

1. Father must be ii, mother must be ii, so all children must be ii. 

2. Father is IAIA (the homozygous one), the mother is IBIB, so the only possibility for the children is IAIB, because you get one allele from the father and one from the mother. 

3. Father is IAi, mother is IBi, so the children can be any of the blood types, because they can have all the combinations of genotypes. 

4. Father is ii, mother is IAIB. Children can only be IAi or IBi. 

5. Father is IAIB, mother is IAIB. Children can be IAIA, IBIB, or IAIB. 

Example of Punnett square: 
3. Father is type A, heterozygous, mother is type B, heterozygous 
Father must be IAi (heterozygous) 
Mother must be IBi (heterozygous) 

_______IA ____ i 

IB____ IBIA____IBi 

i _____ IAi______ii 

Sorry, that was difficult on here, hope it's understandable. 
The father's alleles run across the top, the mother's are on the side, you follow to where they meet to find the possibilities for the children. IBIA (AB blood type), IBi (B), IAi (A), and ii (O) are the possibilities in this case. 

Hope that helps!</span>
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In genetics, Y is related to the dominant allele and y to the recessive one. In this case, having the Y dominant allele determine the color yellow. Therefore, as all of the offspring has the dominant allele Y for yellow, all of the seeds will be yellow, i.e., <u>200 seeds will be yellow</u>.

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