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jeka57 [31]
4 years ago
9

:

Mathematics
1 answer:
Gnoma [55]4 years ago
8 0

Answer:

a is the answer

Step-by-step explanation:

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Roland's Boat Tours sells deluxe and economy seats for each tour it conducts. In order to complete a tour, at least 14 economy s
leonid [27]
The maximum profit would be $1325. Since they make less profit on deluxe seats, you want to get as few of those as possible. You also want to get as many people on the boat as possible, which is 45. The minimum number of deluxe seats you could sell is 5, so that's what we'll use for the max. profit. They make $25 off of each of those seats so 5 times $25 is $125. That leaves 40 economy seats, with a profit of $30 per seat. You have 40 spots left open, so we'll sell 40 economy seats, which will meet your minimum of 14 economy seats. 40 times $30 is $1200. Add $125 and $1200 to get $1325 and you have your maximum profit!
4 0
3 years ago
Select all the expressions that are equivalent to 5x + 30x - 15x
Andrej [43]

Step-by-step explanation:

5(x+6x-3x)

(5+30-15)x

if you open the brackets, it will be 5x+30x-15x

7 0
3 years ago
3(-4x - 3) + 50 - 5= 0
UNO [17]

Answer:

-12x-9+50-5=0

-12x+41-5=0

-12x+36=0

-12x=0-36

x= -36/-12

x = 3 Answer...

hope it helps

7 0
3 years ago
How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi
ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players =  15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formulanCr = \frac{n!}{r!(n - r)!}

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now  we have n = 15 and r = 5

Substituting the values,

15C_5 = \frac{15!}{5!(15- 5)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{360360}{120}

15C_5 = 3003

7 0
3 years ago
PLS HELP WILL GIVE BRAINLIEST
Sonja [21]

Answer:

89 too

Step-by-step explanation:

ok

6 0
3 years ago
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