6th grade math help me pleaseeee

Mathematics

2 answers:

pantera1 [17]2 years ago

5 0

Answer:

its D start from 2 and go to 8

spayn [35]2 years ago

4 0

The answer is D , start from 2 and count to 8 and it gives you your answer

You might be interested in

Solve 2 2/5 - 1 1/2 .

vova2212 [387]

Answer:

9/10

Step-by-step explanation:

2 2/5 - 1 1/2

Get a common denominator of 10

2 2/5 *2/2 = 2 4/10

1 1/2 *5/5 = 1 5/10

2 4/10 - 1 5/10

Borrow from the 2 as 10/10

1 + 10/10 +4/10 - 1 5/10

1 14/10 - 1 5/10

9/10

4 0

3 years ago

Y>= -5x + 8 what is m?

Sonbull [250]

Answer:

The slope = -5

Step-by-step explanation:

y ≥ -5x + 8

Look at the problem as y = -5x + 8 and compare to the slope intercept form. The slope = -5

6 0

3 years ago

Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)

Monica [59]

Answer:

$\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}$

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices $\mathsf{A(x_A, y_A)}$ , $\mathsf{B(x_B, y_B)}$ and $\mathsf{C(x_C, y_C)}$ , have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of <u>analytical geometry</u> is given by the determinant of the vertices divided by two, mathematically,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} \mathsf{x_A} & \mathsf{y_A }& 1 \\ \mathsf{x_B} & \mathsf{ y_B} & 1 \\ \mathsf{ x_C} & \mathsf{ y_C} & 1 \end{array} \right|}{2}$

So, applying this knowledge we're going to have,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2 & -3 & 1 \end{array} \right|}{2}$

$\mathsf{A} \triangle = \dfrac{1}{2}\left[ \left.\begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2& -3 & 1 \end{array} \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]$