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Angelina_Jolie [31]
4 years ago
12

If a system is isolated, the total energy of the system ________. If a system is isolated, the total energy of the system ______

__. depends on the work into the system. increases constantly. depends on the work out of the system. is constant. decreases constantly.
Physics
1 answer:
shutvik [7]4 years ago
8 0

Answer:

Is constant.

Explanation:

Isolated systems cannot exchange energy or matter outside the borders of the system.

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A chain reaction results when a uranium atom is struck by a/an ______________released by a nearby Uranium atom undergoing fissio
finlep [7]

Answer:

Chain reaction is possible by neutron

Explanation:

Nuclear reaction is mainly two types,

⇒ Nuclear Fission : heavy atom split into two light atom.

Ex. Uranium, thorium

⇒ Nuclear fusion : lighter atom combine together

Ex. Hydrogen to helium

In fusion reaction the large amount of energy is produced as compare to fission reaction.

Sun gets brighter by fusion reaction.

In case of uranium fission reaction is possible by colliding neutron.

8 0
4 years ago
A small bulb is rated at 7.5 W when operated at 125 V. The tungsten filament has a temperature coefficient of resistivity α = 0.
alisha [4.7K]

To solve this problem we will apply the concepts related to resistance as a function of temperature, product of the relationship between the squared voltage and the power. Mathematically this is,

R = \frac{v^2}{P}

Here,

R = Resistance (At function of temperature)

v = Voltage

P = Power

Then we have,

R at 140°C (7 times room temperature),

R(140\°C) = \frac{125^2}{7.5}

R(140\°C) = 2083.33\Omega

The relationship between normal temperature and increased temperature would then be given by,

R(140\°C) = R(20\°C)(1 +\alpha (\Delta T))

R(140\°C) = R(20\°C)(1+(4.5*10^{-3})(140-20))

R(20\°C) = \frac{2083.33}{1.54}

R(20\°C) = 1352.81\Omega

Therefore the correct value of the group of answer is 1350

5 0
3 years ago
You did 150 joules of work lifting a 120 -N backpack.
olasank [31]
You did 150.j of work lifting a 120.N back
6 0
3 years ago
The particle accelerator at CERN can accelerate an electron through a potential
asambeis [7]

Answer:

K.E = 1.28 × 10^-17 KeV

Explanation:

Given that a particle accelerator at CERN can accelerate an electron through a potentialdifference of 80 kilovolts.

To Calculate the kinetic energy (in keV) of the electron​, let us first find the electron charge which is 1.60 × 10^-19C

The kinetic energy = work done

K.E = e × kV

Substitute e and the voltage into the formula

K.E = 1.60 × 10^-19 × 80

K.E = 1.28 × 10^-17 KeV

Therefore, the kinetic energy is approximately equal to 1.28 × 10^-17 KeV

8 0
3 years ago
A mercury thermometer is constructed as
Tamiku [17]

Answer:

The change in height of the mercury is approximately  2.981 cm

Explanation:

Recall that the formula for thermal expansion in volume is:

\frac{\Delta V}{V_0} =\alpha_V\, \Delta\, T\\\Delta V = V_0\,\, \alpha_V\,\,\Delta C

from which we solved for the change in volume \Delta V due to a given change in temperature \Delta T

We can estimate the initial volume of the mercury in the spherical bulb of diameter 0.24 cm ( radius R = 0.12 cm) using the formula for the volume of a sphere:

V_0=\frac{4}{3} \pi \, R^3\\V_0=\frac{4}{3} \pi \, (0.12\,cm)^3\\V_0=0.007238\,cm^3

Therefore, the change in volume with a change in temperature of 36°C becomes:

\Delta V = V_0\,\, \alpha_V\,\,\Delta C\\\Delta V = 0.007238229\, cm^3\,(0.000182)\,(36)\\\Delta V=0.0000474248\, cm^3

Now, we can use this difference in volume, to estimate the height of the cylinder of mercury with diameter 0.0045 cm (radius r= 0.00225 cm):

V_{cyl}=\pi r^2\,h\\h =\frac{V_{cyl}}{\pi r^2} \\h=\frac{0.0000474248\, cm^3}{\pi \, (0.00225\,cm)^2} \\h=2.98188 \,cm

8 0
3 years ago
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