Answer:
Friction force on the bullet is 58.7 N opposite to its velocity
Explanation:
As we know that initial speed of the bullet is 55 m/s
after travelling into the sand bag by distance d = 1.34 m it comes to rest
so final speed
now we can use kinematics top find the acceleration of the bullet
so we have
now by Newton's II law we know that
so we have
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13 g —> 0.013 kg
KE = 1/2(m)(v)^2
KE = 1/2(0.013)(8.5)^2
KE = 0.47 J
Answer:
<h3>13,976.23Joules</h3>
Explanation:
Workdone by the rope is expressed using the formula;
W = Fd sin(theta)
F is the tension in the rope = 180
d is the displacement = 300m
theta is the angle of inclination = 15°
Substitute the given parameters into the formula;
W = 180(300)sin15
W = 54000sin 15
W = 13,976.23
Hence the workdone by the rope is 13,976.23Joules
Answer:
It will increase by a factor of 8.
Explanation:
By Ohm's Law, we can relate current, voltage and resistance. It is expressed as V=IR. That is, there is a direct relationship between voltage and resistance and voltage and current.
V = IR
V1/2V1 = I1R1 / I2R1/4
1/2 = 4I1/I2
I2 = 8I1
