What type of line connects the north and South Pole?

Which has greater value, a newton of gold on earth or a newton of gold on the moon?

jek_recluse [69]

The moon, because the acceleration due to gravity is less.

4 0

3 years ago

A 10-cm-long wire is pulled along a u-shaped conducting rail in a perpendicular magnetic field. the total resistance of the wire

Debora [2.8K]

In the above case we can say that power given by external agent to pull the rod must be equal to the power dissipated in the form of heat due to magnetic induction.

Part a)

when we pull the rod with constant speed then power required will be product of force and velocity

here we will have

$P = F.v$

P = 4 W

v = 4 m/s

now we will have

$4 = F*4$

$F = 1N$

So external force required will be 1 N

PART B)

now in order to find magnetic field strength we can say

$P = \frac{v^2B^2L^2}{R}$

here we know that induced EMF in the wire is E = vBL

so power due to induced magnetic field is given by

$P = \frac{E^2}{R}$

$4 = \frac{4^2*B^2*0.10^2}{0.20}$

by solving above equation we will have

$B = 2.24 T$

5 0

3 years ago

When you eat a large meal and your body absorbs a lot of glucose and that makes its way to the interstitial fluid before going i

Agata [3.3K]

Answer:A. It is modified by the cell, so there is still more glucose on the outside of the cell than inside it

Explanation: The cells are the primary unit of a living organism,it is the place where cellular respiration takes place, which is the use of oxygen to break down food substances such as Glucose to release energy in the form of Adenosine trisphosphate (ATP) and give out Carbondioxide as a by-product of cellular respiration.

Most of the Glucose enter the cells to get modified through cellular respiration so their is still more Glucose outside than the Glucose inside.

6 0

3 years ago

Given: Q1 = 3.0 × 10-5 C

Mariulka [41]

$F=k\dfrac{Q_1Q_2}{r^2}= \\ \\ =9\cdot 10^9\cdot \dfrac{3\cdot 10^{-5}\cdot 4\cdot 10^{-5}}{9}=...$

You just do the calculations.

4 0

3 years ago

Read 2 more answers

Pre-laboratory Assignment: Experiment 20 Reflection and Refraction of Light 1. When light is incident on a reflective surface, w

shusha [124]

Answer:

1) ngle of incidence and reflection are equal, light carries does not change

2) the angle of this line with respect to the surface is 90º

3) protractor

4) n₂ sin θ₂ = n_1 sin θ₁, light ray must have a greater angle than the incident ray ,

Explanation:

1) When light falls on a reflective surface, the angle of incidence and reflection are equal and as it travels in the same medium, the speed that the light carries does not change

2) The normal is a line perpendicular to the point of incidence of light, so the angle of this line with respect to the surface is 90º

3) Angles are measured with a protractor

4) When light passes from one medium to another, the speed of the ray changes due to the difference in the refractive index in each medium, due to this change in speed the transmitted light ray must have a greater angle than the incident ray , since the speed increases as the density of the medium decreases

$\frac{sin \theta _2}{ sin \theta_1} = \frac{v_2}{v_1}$

$\frac{c}{v_2} \ sin \theta_2 = \frac{c}{v_1} \ sin \theta_1$

n₂ sin θ₂ = n_1 sin θ₁

6 0

3 years ago