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seraphim [82]
3 years ago
6

DURING A REGULAR HALF-HOUR TV SHOW THERE ARE 8 MINUTES OF COMMERCIALS. IF EACH COMMERCIAL IS 0.25 MINUTES LONG HOW MANY COMMERCI

ALS WILL BE SHOWN DURING THAT SHOW?
Mathematics
2 answers:
kirza4 [7]3 years ago
5 0
Ok so there are 8 min of commercials and if each commercial is .25 minutes. what I did was 8 × 60 to get how many seconds there were. which = 480 and then I did .25 min × 60 and got 15 so I subtracted 15 from 480 and got 7.75
but it says how many commercials so you have to round to the full commercial and you get 8
so I think the answer is 8 or 7.75.
lara31 [8.8K]3 years ago
3 0
8 minutes of total commercial time
0.25 minutes for each commercial
8/0.25=32 commercials on total
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Let x=number of cds and y=number of dvds
Elis [28]
X + y = 40.....multiply by -4
4x + 6y = 180
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-4x - 4y = -160 (result of multiplying by -4)
4x + 6y = 180
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2y = 20
y = 20/2
y = 10 <===

x = 30

6 0
4 years ago
Mandy divided a 12-pound bag of oranges into 5 equal piles. Which rational number represents the weight of the oranges in each p
Gnom [1K]
12÷5= 2.4 pounds

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=2 2/5
8 0
3 years ago
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Write 27/40 as a decimal.
Alecsey [184]

Answer:

0.675

Step-by-step explanation:

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67.5/100

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4 0
3 years ago
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Find the horizontal asymptote
eimsori [14]

Answer:

Correct answer:  h = 3/5  or y = 3/5

Step-by-step explanation:

Given:

h(x) = (3x² - 9x - 4) / (5x² - 4x + 8)

h = lim x -> ∞ (3x² - 9x - 4) / (5x² - 4x + 8) the numerator and denominator will be divided by x² and get

h = lim x -> ∞ (3 - 9(1/x) - 4 (1/x²)) / (5 - 4(1/x) + 8 (1/x²)

The terms 1/x and 1/x²  when x strives ∞ they strives 0

x -> ∞ ⇒ 1/x -> 0  and x -> ∞ ⇒ 1/x² -> 0

h = (3 - 0 - 0) / (5 - 0 + 0)

Horizontal asymptote is h = 3/5 or y = 3/5

God is with you!!!

5 0
4 years ago
Frank has devised a formula for his catering business that calculates the number of meat balls he needs to prepare the formula i
ira [324]

Answer:

96 meatballs are required

Step-by-step explanation:

We know that the formula for he catering business is

m=4a+2c

Where

c= the number of children, m=the number of meat balls, a= the number of adults

So if c = 8  and a = 20 then

m = 4(20) + 2(8)

m = 80 + 16

m = 96

Finally  96 meatballs are required for the party

4 0
4 years ago
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