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Anastaziya [24]
3 years ago
15

The function f(x)=/-x is shown on the graph

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
8 0

we know that

For the function shown on the graph

The domain is the interval--------> (-∞,0]

x\leq0

All real numbers less than or equal to zero

The range is the interval--------> [0,∞)

y\geq 0

All real numbers greater than or equal to zero

so

Statements

<u>case A)</u> The range of the graph is all real numbers less than or equal to 0

The statement is False

Because the range is all numbers greater than or equal to zero

<u>case B)</u> The domain of the graph is all real numbers less than or equal to 0

The statement is True

See the procedure

<u>case C)</u> The domain and range of the graph are the same

The statement is False

Because the domain is all real numbers less than or equal to zero and the range is is all numbers greater than or equal to zero

<u>case D)</u> The range of the graph is all real numbers

The statement is False

Because the range is all numbers greater than or equal to zero

therefore

<u>the answer is</u>

The domain of the graph is all real numbers less than or equal to 0



levacccp [35]3 years ago
4 0

Answer:

The domain of the graph is all real numbers less than or equal to 0.

Step-by-step explanation:

Given : f(x) = -x

To Find: which statement is correct?

Solution:

Domain : The domain is the set of all possible x-values which will make the function "work", and will output real y-values.

Range : The range is the resulting y-values we get after substituting all the possible x-values.

The function shown on the graph

The domain is the interval :(-∞,0]

x\leq0

So, Domain of f(x) = -x : All real numbers less than or equal to zero

The range is the interval: [0,∞)

y\geq 0

So,Range of f(x) = -x:All real numbers greater than equal to 0 .

Thus Option B is correct.

The domain of the graph is all real numbers less than or equal to 0.

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antiseptic1488 [7]

Answer:

OBC= 15

OCR =30

In OBQ

OBQ + QOB + OQB = 180

OBQ= OBC=15

OQB= 90

SO, QOB = 180- OBQ- OQB

= 180-15 -90

= 75

c) is correct

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