Answer:
y=3x
Step-by-step explanation:
Use a calculator to guess and check
Flip a coin twenty five times, the purpose of this is to show that theoretical and experimental do not always overlap.
Theoretically, it should be a fifty-fifty chance.
In the experiment because you do it a odd amount of times, 25, each flip will be worth a four percent chance.
You would not be able to make a fifty fifty chance with that amount of flips.
Also here:
1.) 13 Heads, 12 tails
2.) 48% chance for the coin to land on tails, 52% chance for the coin to land on heads.
3.) The theoretical probability of a coin landing on heads is 50% of the time that the coin is flipped. This is because there are two possibilities with an equal likelihood of happening
4) The theoretical probability and experimental probability are different as theoretically there would be an equal likelihood or probability and in the experiement, there was a higher probability for the coin to land on heads.
Answer:
The second ramp needs to have 25°.
Step-by-step explanation:
Required ramp angle for driving the car from the ground = 35°.
First ramp angle = 15°
Therefore, second ramp angle equals required ramp angle minus first ramp angle, which is = 35° - 15° = 20°
The 20° ramp angle will make the total ramp angle to be equal to 35°.
That is 15° + 20° = 35°
11 and 2/11 because 46 divided by 11 is 44 plus 2 is 46
Let Xi be the random variable representing the number of units the first worker produces in day i.
Define X = X1 + X2 + X3 + X4 + X5 as the random variable representing the number of units the
first worker produces during the entire week. It is easy to prove that X is normally distributed with mean µx = 5·75 = 375 and standard deviation σx = 20√5.
Similarly, define random variables Y1, Y2,...,Y5 representing the number of units produces by
the second worker during each of the five days and define Y = Y1 + Y2 + Y3 + Y4 + Y5. Again, Y is normally distributed with mean µy = 5·65 = 325 and standard deviation σy = 25√5. Of course, we assume that X and Y are independent. The problem asks for P(X > Y ) or in other words for P(X −Y > 0). It is a quite surprising fact that the random variable U = X−Y , the difference between X and Y , is also normally distributed with mean µU = µx−µy = 375−325 = 50 and standard deviation σU, where σ2 U = σ2 x+σ2 y = 400·5+625·5 = 1025·5 = 5125. It follows that σU = √5125. A reference to the above fact can be found online at http://mathworld.wolfram.com/NormalDifferenceDistribution.html.
Now everything reduces to finding P(U > 0) P(U > 0) = P(U −50 √5125 > − 50 √5125)≈ P(Z > −0.69843) ≈ 0.757546 .
